不確定如何做到這一點，猜測 C# LINQ 可能是可能的。所以我有一個對象：public class NContainer { public string _HostFqdn { get; set; } public string _HostIp { get; set; } public int _Severity { get; set; } public string _Issue { get; set; } public string _ProtoPort { get; set; } }我給它一個如下列表：List<NContainer> nList = new List<NContainer>();nList.Add( new NContainer { _HostFqdn = "ab1.corp.com", _HostIp = "192.168.0.2", _Severity = 1, _Issue = "Check 1", _ProtoPort = "TCP_80" } );nList.Add( new NContainer { _HostFqdn = "ab2.corp.com", _HostIp = "192.168.0.3", _Severity = 2, _Issue = "Check 2", _ProtoPort = "TCP_81" } );nList.Add( new NContainer { _HostFqdn = "ab3.corp.com", _HostIp = "192.168.0.4", _Severity = 1, _Issue = "Check 2", _ProtoPort = "TCP_82" } );nList.Add( new NContainer { _HostFqdn = "ab4.corp.com", _HostIp = "192.168.0.5", _Severity = 3, _Issue = "Check 1", _ProtoPort = "TCP_80" } );nList.Add( new NContainer { _HostFqdn = "ab5.corp.com", _HostIp = "192.168.0.6", _Severity = 3, _Issue = "Check 5", _ProtoPort = "TCP_443" } );nList.Add( new NContainer { _HostFqdn = "ab6.corp.com", _HostIp = "192.168.0.7", _Severity = 4, _Issue = "Check 1", _ProtoPort = "TCP_80" } );我希望能夠在上面的列表中運行 LINQ 查詢（或類似查詢），以便控制臺輸出采用以下格式：Group By _Issue Check 1 192.168.0.2 TCP_80 192.168.0.5 TCP_82 192.168.0.7 TCP_80 Check 2 192.168.0.3 TCP_81 192.168.0.4 TCP_82 Check 5 192.168.0.6 TCP_443我可以使用類似于下面的代碼顯示 List 和 orderby 的內容，但不知道如何以上面的格式顯示輸出？List<NContainer> arrList = new List<NContainer>();List<NContainer> query = from NContainer vulns in arrList orderby vulns._Issue where vulns._Severity >= 1 select vulns; foreach (var vuln in query) { Console.WriteLine("{0}", vuln._Issue, vuln._HostIp, vuln._ProtoPort); }
2 回答
精慕HU
TA貢獻1845條經驗 獲得超8個贊
您可以按 _Issue 分組并寫入控制臺，如下所示
var results = nList.GroupBy(x=>x._Issue);
Console.WriteLine("Group By _Issue");
foreach(var item in results)
{
Console.WriteLine(item.Key);
var IpString = string.Join(" ",item.ToList().Select(x=> $"{x._HostIp} {x._ProtoPort}"));
Console.WriteLine(IpString);
Console.WriteLine();
}
輸出
Group By _Issue
Check 1
192.168.0.2 TCP_80 192.168.0.5 TCP_80 192.168.0.7 TCP_80
Check 2
192.168.0.3 TCP_81 192.168.0.4 TCP_82
Check 5
192.168.0.6 TCP_443
千巷貓影
TA貢獻1829條經驗 獲得超7個贊
可能有更好的方法來做到這一點，但這有效：
List<NContainer> nList = new List<NContainer>();
nList.Add(new NContainer { _HostFqdn = "ab1.corp.com", _HostIp = "192.168.0.2", _Severity = 1, _Issue = "Check 1", _ProtoPort = "TCP_80" });
nList.Add(new NContainer { _HostFqdn = "ab2.corp.com", _HostIp = "192.168.0.3", _Severity = 2, _Issue = "Check 2", _ProtoPort = "TCP_81" });
nList.Add(new NContainer { _HostFqdn = "ab3.corp.com", _HostIp = "192.168.0.4", _Severity = 1, _Issue = "Check 2", _ProtoPort = "TCP_82" });
nList.Add(new NContainer { _HostFqdn = "ab4.corp.com", _HostIp = "192.168.0.5", _Severity = 3, _Issue = "Check 1", _ProtoPort = "TCP_80" });
nList.Add(new NContainer { _HostFqdn = "ab5.corp.com", _HostIp = "192.168.0.6", _Severity = 3, _Issue = "Check 5", _ProtoPort = "TCP_443" });
nList.Add(new NContainer { _HostFqdn = "ab6.corp.com", _HostIp = "192.168.0.7", _Severity = 4, _Issue = "Check 1", _ProtoPort = "TCP_80" });
IEnumerable<NContainer> query = from NContainer vulns in nList
orderby vulns._Issue
where vulns._Severity >= 1
select vulns;
Console.WriteLine("Group by _Issue");
var prevIssue = "";
bool first = true;
foreach (var vuln in query)
{
if (prevIssue != vuln._Issue)
{
if (first)
first = false;
else
Console.WriteLine("\n");
Console.WriteLine("\t{0}", vuln._Issue);
Console.Write("\t");
prevIssue = vuln._Issue;
}
Console.Write("{0} {1} ", vuln._HostIp, vuln._ProtoPort);
}
基本上使用 Console.Write 而不是 WriteLine 以便您可以循環并將特定信息的所有 IP 信息附加到同一行。其余的只是格式化。
- 2 回答
- 0 關注
- 114 瀏覽
添加回答
舉報
0/150
提交
取消