我試圖弄清楚為什么此代碼不適用于 Google Apps Script Web 應用程序 URL，但它會與隨機 Web API URL 一起使用？第一個代碼塊從虛擬 API 獲取數據。第二個代碼塊不會從 Google Apps 腳本網絡應用 URL 中返回任何內容。代碼中唯一的區別是 $url 變量值。GAS 應用程序設置為 Web 應用程序，因此任何人，甚至匿名者都可以訪問它（下面的屏幕截圖）。如果我直接轉到 GAS url GAS Output，它會返回 JSON。Google Apps 腳本代碼在下面的第三個代碼塊中。有任何想法嗎？感謝 Tanaike 解決了問題！工作代碼粘貼在問題的底部。第一個代碼塊<?php// Initiate curl session in a variable (resource)$curl_handle = curl_init();$url = "http://dummy.restapiexample.com/api/v1/employees";// Set the curl URL optioncurl_setopt($curl_handle, CURLOPT_URL, $url);// This option will return data as a string instead of direct outputcurl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, true);// Execute curl & store data in a variable$curl_data = curl_exec($curl_handle);curl_close($curl_handle);// Decode JSON into PHP array$user_data = json_decode($curl_data);// Print all data if neededprint_r($user_data);?>第二個代碼塊<?php// Initiate curl session in a variable (resource)$curl_handle = curl_init();$url = "https://script.google.com/macros/s/AKfycbyWSDzUyFa41fu_6QWP7h8ToklwWysGZsuSPaRnu649DmPNYG8/exec";// Set the curl URL optioncurl_setopt($curl_handle, CURLOPT_URL, $url);// This option will return data as a string instead of direct outputcurl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, true);// Execute curl & store data in a variable$curl_data = curl_exec($curl_handle);curl_close($curl_handle);// Decode JSON into PHP array$user_data = json_decode($curl_data);// Print all data if neededprint_r($user_data);?>第一個代碼塊：GAS 代碼function doGet(e) {  var data = {    status: 'success',    dataSet: 'Some Info'  };  var output = JSON.stringify(data);  return ContentService.createTextOutput(output).setMimeType(ContentService.MimeType.JSON);}工作代碼，謝謝Tanaike！<?php// Initiate curl session in a variable (resource)$curl_handle = curl_init();$url = "https://script.google.com/macros/s/AKfycbyWSDzUyFa41fu_6QWP7h8ToklwWysGZsuSPaRnu649DmPNYG8/exec";