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如何通過 lodash groupBy() 區分基于帶鍵和不帶鍵的 JSON？

JavaScript

忽然笑 2022-07-21 10:38:41

lodash 的結果groupBy()應該是{ "withType": [], "withOutType": [] }.const splittedData = _.groupBy(datas, 'type', 'withOutType');type是否可以根據JSON中鍵的存在區分為兩組？const datas=[{_id:"5ea2ecbde53c090b4ba4fa12",firstName:"Dillon",surname:"Mclaughlin",guid:"a727438f-4ddc-4422-af4a-c7396fda73c3",isActive:true,balance:"$3,331.33",picture:"http://placehold.it/32x32",age:37,type:"student"},{_id:"5ea2ecbd067a8ad1cb1f9e62",firstName:"Fleming",surname:"Austin",guid:"e228bbea-ef6b-4709-995c-bf485fa3665c",isActive:true,balance:"$1,869.92",picture:"http://placehold.it/32x32",age:35,type:"teacher"},{_id:"5ea2ecbd0d1a074b255a1349",firstName:"Kaufman",surname:"Alford",guid:"176fb7fe-b7bc-4574-8887-4252a042b24a",isActive:true,balance:"$2,163.34",picture:"http://placehold.it/32x32",age:29,type:"student"},{_id:"5ea2ecbd1162ee44119aa0d3",firstName:"Sykes",surname:"Petty",guid:"92b13963-7d32-469c-be80-c88728a7842a",isActive:false,balance:"$2,728.46",picture:"http://placehold.it/32x32",age:37},{_id:"5ea2ecbd297854a2f85909a4",firstName:"Stuart",surname:"Pickett",guid:"322031f9-1a71-44ae-b1cf-cbe7430b78b6",isActive:false,balance:"$1,725.25",picture:"http://placehold.it/32x32",age:25,type:"student"},{_id:"5ea2ecbd6ef4a9bee37a223a",firstName:"Berg",surname:"Hewitt",guid:"ab05bed9-29e4-4570-aa12-fead954417b0",isActive:false,balance:"$2,935.72",picture:"http://placehold.it/32x32",age:31}];const splittedData = _.groupBy(datas, 'type', 'noneType');console.log(splittedData);<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.min.js"></script>預期結果{ "withType": [], "withOutType": []}

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4 回答

犯罪嫌疑人X

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用于_.partition()創建兩組 - 一組用于真實值，另一組用于虛假值。解構并創建對象：

const datas=[{_id:"5ea2ecbde53c090b4ba4fa12",firstName:"Dillon",surname:"Mclaughlin",guid:"a727438f-4ddc-4422-af4a-c7396fda73c3",isActive:true,balance:"$3,331.33",picture:"http://placehold.it/32x32",age:37,type:"student"},{_id:"5ea2ecbd067a8ad1cb1f9e62",firstName:"Fleming",surname:"Austin",guid:"e228bbea-ef6b-4709-995c-bf485fa3665c",isActive:true,balance:"$1,869.92",picture:"http://placehold.it/32x32",age:35,type:"teacher"},{_id:"5ea2ecbd0d1a074b255a1349",firstName:"Kaufman",surname:"Alford",guid:"176fb7fe-b7bc-4574-8887-4252a042b24a",isActive:true,balance:"$2,163.34",picture:"http://placehold.it/32x32",age:29,type:"student"},{_id:"5ea2ecbd1162ee44119aa0d3",firstName:"Sykes",surname:"Petty",guid:"92b13963-7d32-469c-be80-c88728a7842a",isActive:false,balance:"$2,728.46",picture:"http://placehold.it/32x32",age:37},{_id:"5ea2ecbd297854a2f85909a4",firstName:"Stuart",surname:"Pickett",guid:"322031f9-1a71-44ae-b1cf-cbe7430b78b6",isActive:false,balance:"$1,725.25",picture:"http://placehold.it/32x32",age:25,type:"student"},{_id:"5ea2ecbd6ef4a9bee37a223a",firstName:"Berg",surname:"Hewitt",guid:"ab05bed9-29e4-4570-aa12-fead954417b0",isActive:false,balance:"$2,935.72",picture:"http://placehold.it/32x32",age:31}];

const [withType, withoutType] = _.partition(datas, 'type');

console.log({ withType, withoutType });

.as-console-wrapper { max-height: 100% !important; top: 0; }

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隔江千里

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您可以提供一個函數作為第二個參數，_.groupBy()如果'withType'當前對象具有該type屬性（使用檢查_.has()），'withoutType'則該函數將返回，否則將返回：

const data = [{_id:"5ea2ecbde53c090b4ba4fa12",firstName:"Dillon",surname:"Mclaughlin",guid:"a727438f-4ddc-4422-af4a-c7396fda73c3",isActive:true,balance:"$3,331.33",picture:"http://placehold.it/32x32",age:37,type:"student"},{_id:"5ea2ecbd067a8ad1cb1f9e62",firstName:"Fleming",surname:"Austin",guid:"e228bbea-ef6b-4709-995c-bf485fa3665c",isActive:true,balance:"$1,869.92",picture:"http://placehold.it/32x32",age:35,type:"teacher"},{_id:"5ea2ecbd0d1a074b255a1349",firstName:"Kaufman",surname:"Alford",guid:"176fb7fe-b7bc-4574-8887-4252a042b24a",isActive:true,balance:"$2,163.34",picture:"http://placehold.it/32x32",age:29,type:"student"},{_id:"5ea2ecbd1162ee44119aa0d3",firstName:"Sykes",surname:"Petty",guid:"92b13963-7d32-469c-be80-c88728a7842a",isActive:false,balance:"$2,728.46",picture:"http://placehold.it/32x32",age:37},{_id:"5ea2ecbd297854a2f85909a4",firstName:"Stuart",surname:"Pickett",guid:"322031f9-1a71-44ae-b1cf-cbe7430b78b6",isActive:false,balance:"$1,725.25",picture:"http://placehold.it/32x32",age:25,type:"student"},{_id:"5ea2ecbd6ef4a9bee37a223a",firstName:"Berg",surname:"Hewitt",guid:"ab05bed9-29e4-4570-aa12-fead954417b0",isActive:false,balance:"$2,935.72",picture:"http://placehold.it/32x32",age:31}];

const splittedData = _.groupBy(data, o => _.has(o, 'type') ? 'withType' : 'withoutType');

console.log(splittedData);

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qq_笑_17

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您可以檢查對象中是否存在并獲取按或type分組的對象。truefalse

const splittedData = _.groupBy(datas, o => 'type' in o ? "withType" : "withOutType");

console.log(splittedData);

.as-console-wrapper { max-height: 100% !important; top: 0; }

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收到一只叮咚

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我看到這樣的解決方案：

const splits = [

[...datas.filter(element => element.type)],

[...datas.filter(element => !element.type)]

]

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如何通過 lodash groupBy() 區分基于帶鍵和不帶鍵的 JSON？

如何通過 lodash groupBy() 區分基于帶鍵和不帶鍵的 JSON？

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如何通過 lodash groupBy() 區分基于帶鍵和不帶鍵的 JSON？

如何通過 lodash groupBy() 區分基于帶鍵和不帶鍵的 JSON？