所以我想計算兩個日期選擇器之間的天數。所以我嘗試制作兩個數組，但沒有任何想法？這是我的日期選擇器
4 回答
楊魅力
TA貢獻1811條經驗 獲得超6個贊
public static int getDaysBetweenDates(Date fromDate, Date toDate) {
return Math.abs((int) ((toDate.getTime() - fromDate.getTime()) / (1000 * 60 * 60 * 24)));
}
人到中年有點甜
TA貢獻1895條經驗 獲得超7個贊
將日歷字符串日、月、年轉換為日期類。
更多討論：Java 字符串到日期轉換
例如
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");
Date d1, d2;
try {
d1 = dateFormat.parse(year + "-" + month + "-" + day); //as per your example
d2 = //do the same thing as above
long days = getDifferenceDays(d1, d2);
}
catch (ParseException e) {
e.printStackTrace();
}
public static long getDifferenceDays(Date d1, Date d2) {
long diff = d2.getTime() - d1.getTime();
return TimeUnit.DAYS.convert(diff, TimeUnit.MILLISECONDS);
}
慕標5832272
TA貢獻1966條經驗 獲得超4個贊
Scanner in = new Scanner(System.in);
int n = in.nextInt();
Date d1, d2;
Calendar cal = Calendar.getInstance();
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
sdf.setTimeZone(TimeZone.getTimeZone("UTC"));
for (int i = 0; i < n; i++) {
try {
d2 = sdf.parse(in.next());
d1 = sdf.parse(in.next());
long differene = (d2.getTime() - d1.getTime()) / (1000 * 60 * 60 * 24);
System.out.println(Math.abs(differene));
} catch (Exception e) {
}
}
qq_花開花謝_0
TA貢獻1835條經驗 獲得超7個贊
創建一個方法getDates()
private static ArrayList<Date> getDates(String dateString1, String dateString2)
{
ArrayList<Date> arrayofdates = new ArrayList<Date>();
DateFormat df1 = new SimpleDateFormat("dd-MM-yyyy");
Date date1 = null;
Date date2 = null;
try {
date1 = df1 .parse(dateString1);
date2 = df1 .parse(dateString2);
} catch (ParseException e) {
e.printStackTrace();
}
Calendar calender1 = Calendar.getInstance();
Calendar calendar2 = Calendar.getInstance();
calender1.setTime(date1);
calender2.setTime(date2);
while(!calender1.after(calender2))
{
arrayofdates.add(calender1.getTime());
calender1.add(Calendar.DATE, 1);
}
return arrayofdates;
}
然后在此方法中傳遞參數以獲取日期數組當您使用 DatePicker 然后
DateFormat df1 = new SimpleDateFormat("dd-MM-yyyy");
ArrayList<Date> mBaseDateList = getDates(df1.format(cal1.time), df1.format(cal2.time))
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