首頁猿問正則表達式匹配直到Java中的文本結尾

正則表達式匹配直到Java中的文本結尾

Java

慕工程0101907 2022-07-20 12:14:36

我想使用正則表達式獲取 From 字段的所有電子郵件地址，例如獲取所有以“From：”開頭并以“/n”新行結尾的文本行。這是我要應用此正則表達式的完整文本，Sent: Tue Mar 05 15:42:11 IST 2019From: [email protected]: [email protected]: Re: Foausrnisfseur invadlide (030000000000:3143)Message: ----------------------------Sent: Tue Mar 05 15:40:51 IST 2019From: [email protected]: [email protected]: Foausrnisfseur invadlide (O4562000888885456:3143)Message:This is not right please correctTermes de paiement Foausrnisfseur non spécifiésimpact potentiel: 3 000,00You should write From field with [email protected] not From: field with [email protected] in the columnDate détecté: 2019-02-26 12:55:03---- Please do not delete or modify this line. (2423000000000149:3143) -----------------------------Sent: Tue Mar 05 15:40:51 IST 2019From: [email protected]: [email protected]: Foausrnisfseur invadlide (O4562000888885456:3143)我嘗試了以下模式，但沒有奏效，[^.?!]*(?<=[.?\s!])string(?:(?=[\s.?!])[^.?!]*(?:[.?!].*)?)?$ /^([\w\s\.]*)string([\w\s\.]*)$/ "^\\w*\\s*((?m)Name.*$)"上述文本預期的預期結果是：[email protected], [email protected], [email protected],PS。我想要 Java 邏輯的正則表達式

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4 回答

慕村225694

TA貢獻1880條經驗獲得超4個贊

針對您的情況使用此正則表達式：

From:\s+([\w-]+@([\w-]+\.)+[\w-]+)

我已經用https://www.freeformatter.com/java-regex-tester.html#ad-output嘗試了這個正則表達式，它符合您的要求。

您需要的比賽在捕獲組 1 中。

工作演示：https ://regex101.com/r/dGaPbD/4

反對回復 2022-07-20

郎朗坤

TA貢獻1921條經驗獲得超9個贊

String emailRegex = "[^\\s]+"; // Replace with a better one

Matcher m = Pattern.compile("(?m)^From:\\s*(" + emailRegex + ")\\s*$").matcher(yourString);

List<String> allMatches = new ArrayList<String>();

while(m.find())

System.out.println(m.group(1));

反對回復 2022-07-20

波斯汪

TA貢獻1811條經驗獲得超4個贊

String test = " Sent: Tue Mar 05 15:42:11 IST 2019 "

+ " From: [email protected] "

+ " To: [email protected] "

+ " Subject: Re: Foausrnisfseur invadlide (030000000000:3143) "

+ " Message: "

+ " "

+ " ---------------------------- "

+ " "

+ " Sent: Tue Mar 05 15:40:51 IST 2019 "

+ " From: [email protected] "

+ " To: [email protected] "

+ " Subject: Foausrnisfseur invadlide (O4562000888885456:3143) "

+ " Message: "

+ " This is not right please correct "

+ " Termes de paiement Foausrnisfseur non spécifiés "

+ " impact potentiel: 3 000,00 "

+ " You should write From field with [email protected] "

+ " and not From: field with [email protected] in the column "

+ " Date détecté: 2019-02-26 12:55:03 "

+ " "

+ " ---- Please do not delete or modify this line. (2423000000000149:3143) ---- "

+ " " + " ------------------------- "

+ " Sent: Tue Mar 05 15:40:51 IST 2019 " + " From: [email protected] "

+ " To: [email protected] "

+ " Subject: Foausrnisfseur invadlide (O4562000888885456:3143) ";

String emailRegex = "[a-zA-Z0-9._%+-]+@[A-Za-z0-9.-]+\\.[a-zA-Z]{2,6}";

Pattern pattern = Pattern.compile("From\\:\\s(" + emailRegex + ")");// From\\:\\s same as Form : and () here i added Email Id regex or you also change to (.*\n) but not recommended

Matcher match = pattern.matcher(test);

while (match.find()) {

System.out.println(match.group(1));

}

輸出：

[email protected]

反對回復 2022-07-20

不負相思意

TA貢獻1777條經驗獲得超10個贊

試試這個模式：^From:\s*(\S+)$

它首先用匹配行首^，然后匹配From:字面意思，然后用匹配 0 個或多個空格\s*，然后匹配一個或多個非空格并將其存儲在捕獲組中，$匹配行尾。

要獲取電子郵件地址，只需使用第一個捕獲組的值。

演示

反對回復 2022-07-20

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正則表達式匹配直到Java中的文本結尾

正則表達式匹配直到Java中的文本結尾

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