我正在嘗試讀取二進制文件以從不同位置獲取字符串；讀取 {IP,login,pwd} 我的想法是找到第一個 ip 并在之后讀取數據，因為之間的長度是一樣的：Offset(h) 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F00000060 5F 00 00 00 00 11 E0 BB 5F 00 00 00 00 01 34 31 _.....à?_.....4000000070 2E 31 39 31 2E 39 37 2E 36 32 00 00 00 00 00 00 .091.17.02......00000080 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................00000090 00 00 73 75 70 70 6F 72 74 00 00 00 00 00 00 00 ..support.......000000A0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................000000B0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................000000C0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................000000D0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................000000E0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................000000F0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................00000100 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................00000110 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................00000120 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................00000130 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................00000140 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................00000150 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................00000160 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................00000170 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................我的圍棋代碼import ( "io" "log" "os")func main() { file, err := os.Open("data") if err != nil { log.Fatal(err) } defer file.Close() o2, err := file.Seek(110, io.SeekCurrent) <---- find first occurrence byteSlice := make([]byte, 32) bytesRead, err := file.Read(byteSlice) if err != nil { log.Fatal(err) } log.Printf("IP: %s\n", byteSlice) }如何在找到 ip 后找到所有出現的 { ip, login, pwd }，用我的代碼我只能找到第一個 (ip) 32 位。去
2 回答
皈依舞
TA貢獻1851條經驗 獲得超3個贊
謝謝你的幫助，
我使用 file.Seek(x,0) 像這樣的代碼：
file, err := os.Open("data.bin")
check(err)
defer file.Close()
o1, err := file.Seek(110, 0) <--- first position
check(err)
_ip := make([]byte, 15)
ipRead, err := file.Read(_ip)
clean_ip := strings.ReplaceAll(string(_ip[:]), " ", " ")
o2, err := file.Seek(21, io.SeekCurrent)
check(err)
_user := make([]byte, 15)
userRead, err := file.Read(_user)
clean_user := strings.ReplaceAll(string(_user[:]), " ", " ")
o3, err := file.Seek(532, 0) <---- Second position
check(err)
_pwd := make([]byte, 20)
pwdRead, err := file.Read(_pwd)
clean_pwd := strings.ReplaceAll(string(_pwd[:]), " ", " ")
它的工作但不干凈
繁花如伊
TA貢獻2012條經驗 獲得超12個贊
一種方法是迭代文件。本質上，您可以重新實現該strings程序。它類似于使用bufio#Scanner.Scan，但您需要迭代空字節而不是換行符。您可以使用 bufio#Scanner.Split，Go 甚至提供了一些預制功能。
我采用了ScanLines并修改為使用空字節而不是換行符。此外，也 ScanLines返回空行，所以我添加了一個空文本檢查：
package main
import (
"bufio"
"strings"
)
func null(b []byte, eof bool) (int, []byte, error) {
if eof { return 0, nil, nil }
for n := range b {
if b[n] == 0 {
return n+1, b[:n], nil
}
}
return len(b), b, nil
}
func main() {
s := bufio.NewScanner(strings.NewReader("March\x00April\x00May\x00\x00June"))
s.Split(null)
for s.Scan() {
if s.Text() != "" {
println(s.Text())
}
}
}
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