我寫了 2 個函數v1GetSessionID和v1SessionIDforBind。/* * v1GetSessionID */func v1GetSessionID(c *gin.Context, app *firebase.App, client *firestore.Client, stripcallGetSession func() func(internalUserID string, customerID string) (sessionid string, err error)) (sessionid string, err error) { defer erapse.ShowErapsedTIme(time.Now()) idToken := c.Param("idToken") user, err := idToken2User(app, idToken) if err != nil {return} customerID, err := user.getCustomerID() if err != nil {return} sessionid, err = stripcallGetSession()(user.getInternalID(), customerID) return}/* * v1SessionIDforBind */func v1SessionIDforBind(c *gin.Context, app *firebase.App, client *firestore.Client) { defer erapse.ShowErapsedTIme(time.Now()) var requestBody JsonPurchaseBindSessionRequest if err := c.ShouldBindJSON(&requestBody); err != nil { okngErrorOut(c, err) return } stripcallGetSession := func() func(internalUserID string, customerID string) (sessionid string, err error) { return func(internalUserID string, customerID string)(sessionid string, err error){return stripeGetSessionIDforBind(requestBody, internalUserID, customerID)} } sessionid, err := v1GetSessionID(c, app, client, stripcallGetSession)() if err != nil { log.Println(err) okngErrorOut(c, err) } else { c.JSON(http.StatusOK, gin.H{ "SessionID": sessionid, }) }}在后一個函數的中間,我將前者稱為如下; sessionid, err := v1GetSessionID(c, app, client, stripcallGetSession)()但是 go 編譯器在單值上下文中將其指示為多值。go run *.go# command-line-arguments./v1handler.go:332:34: multiple-value v1GetSessionID() in single-value contextv1GetSessionID 返回 sessionid 字符串的 2 個值,err 錯誤,我已通過sessionid,err收到它。那么為什么我有上面提到的錯誤呢?go 版本為:go1.14.4 linux/arm。
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飲歌長嘯
TA貢獻1951條經驗 獲得超3個贊
在對 v1GetSessionID() 的調用中有一組額外的括號。你用 4 個參數調用它,它會返回兩個這樣的值。但是通過在初始調用之后放置額外的括號,您要求 Go 然后執行返回值,就好像它是一個函數一樣,這就是編譯器似乎在抱怨的。簡單示例: https: //play.golang.org/p/ZX9kp6rxA09
只需刪除第二組括號,它應該可以編譯:
sessionid, err := v1GetSessionID(c, app, client, stripcallGetSession)
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