我想創建一個在 Javascript 中交換數組的 2 個元素的函數，所以我創建了這段代碼：let arrayOne = ["elementA","elementB","elementC","elementD","elementE","elementF","elementG","elementH","elementI"];function swapThatFails(element1,element2) {    arrayOne[arrayOne.indexOf(element1)] = element2;    arrayOne[arrayOne.indexOf(element2)] = element1;    console.log("arrayOne = ",arrayOne);}swapThatFails ("elementA", "elementC");但是，它對原始數組沒有任何改變。我設法通過獲取要交換的數組的索引來使其工作：let arrayTwo = ["elementA","elementB","elementC","elementD","elementE","elementF","elementG","elementH","elementI"];function swapThatWorks(element1,element2) {    let index1 = arrayTwo.indexOf(element1);    let index2 = arrayTwo.indexOf(element2);    arrayTwo[index1] = element2;    arrayTwo[index2] = element1;    console.log("arrayTwo = ",arrayTwo);}swapThatWorks ("elementA", "elementC");對我來說，它們都是相同的，除了第二個是分兩步完成的，所以看起來更容易理解。為什么第一個不起作用，而第二個起作用？let arrayOne = ["elementA","elementB","elementC","elementD","elementE","elementF","elementG","elementH","elementI"];let arrayTwo = ["elementA","elementB","elementC","elementD","elementE","elementF","elementG","elementH","elementI"];function swapThatFails(element1,element2) {    arrayOne[arrayOne.indexOf(element1)] = element2;    arrayOne[arrayOne.indexOf(element2)] = element1;    console.log("arrayOne = ",arrayOne);  }function swapThatWorks(element1,element2) {    let index1 = arrayTwo.indexOf(element1);    let index2 = arrayTwo.indexOf(element2);    arrayTwo[index1] = element2;    arrayTwo[index2] = element1;    console.log("arrayTwo = ",arrayTwo);  }  swapThatFails ("elementA", "elementC");swapThatWorks ("elementA", "elementC");