在 Spring Boot 中，我創建了具有特定狀態代碼的自定義異常類，并調用它以在控制器上拋出異常代碼：100 和消息：“沒有內容”，但輸出仍然返回“狀態”：500 和“錯誤”： “內部服務器錯誤”AppException.javapublic class AppException extends RuntimeException { private static final long serialVersionUID = 1L; private final Integer code; public AppException(Integer code, String message) { super(message); this.code = code; } public Integer getCode() { return code; }}UserController.java@RestController@RequestMapping("/api/user")public class UserController { @Autowired private UserService userService; @GetMapping() public ApiResponseDto getAllUsers(Pageable pageable) { Page<User> users = userService.getAllUsers(pageable); if (users.getSize() < 0) { throw new AppException(100, "No have content"); } return new ApiResponseDto(HttpStatus.OK.value(), users); }實際輸出：{ "timestamp": 1550987372934, "status": 500, "error": "Internal Server Error", "exception": "com.app.core.exception.AppException", "message": "No have content", "path": "/api/user"}我的期望：{ "timestamp": 1550987372934, "status": 100, "error": "No have content", "exception": "com.app.core.exception.AppException", "message": "No have content", "path": "/api/user"}
3 回答
九州編程
TA貢獻1785條經驗 獲得超4個贊
如果您希望對 API 進行全局異常處理，并且更喜歡自定義錯誤響應，您可以添加@ControllerAdvice：
@ControllerAdvice
public class ApiExceptionHandler {
@ExceptionHandler({ ApiException.class })
protected ResponseEntity<ApiErrorResponse> handleApiException(ApiException ex) {
return new ResponseEntity<>(new ApiErrorResponse(ex.getStatus(), ex.getMessage(), Instant.now()), ex.getStatus());
}
}
// you can put any information you want in ApiErrorResponse
public class ApiErrorResponse {
private final HttpStatus status;
private final String message;
private final Instant timestamp;
public ApiError(HttpStatus status, String message, Instant timestamp) {
this.status= status;
this.message = message;
this.timestamp = timestamp;
}
public HttpStatus getStatus() {
return this.status;
}
public String getMessage() {
return this.message;
}
public Instant getTimestamp() {
return this.timestamp;
}
}
// your custom ApiException class
public class ApiException extends RuntimeException {
private final HttpStatus status;
public ApiException(HttpStatus status, String message) {
super(message);
this.status = status;
}
public HttpStatus getStatus() {
return this.status;
}
}
蕪湖不蕪
TA貢獻1796條經驗 獲得超7個贊
如果您需要有限數量的不同錯誤消息，或者您想多次重復使用相同的錯誤消息，那么您只需要這樣：
@ResponseStatus(value = HttpStatus.CONTINUE, reason = "No have content")
public class AppException extends RuntimeException {
private static final long serialVersionUID = 1L;
}
不需要任何額外的類和處理程序。您的代碼將清晰而簡單。
您可以像這樣簡單地提高它：
throw new AppException();
慕碼人8056858
TA貢獻1803條經驗 獲得超6個贊
有多種方法可以實現這一點：
異常處理程序
您可以@ExceptionHandler在控制器中添加帶注釋的方法：
@ExceptionHandler({ CustomException1.class, CustomException2.class })
public void handleException() {
//
}
處理程序異常解析器
您還可以實現自定義解析器來攔截所有異常并通過覆蓋doResolveException方法來全局處理它們
可以在此處找到有關上述兩種方法的更多詳細信息：https ://www.baeldung.com/exception-handling-for-rest-with-spring
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