我試圖制作一個非常簡單的文本計算器，但我一直遇到這個問題。這是我的代碼：num1 = input("Enter in the first number")num2 = input("Enter in the second number")sign = input("Enter in the calculator operator you would like")elif sign = "+": print(num1 + num2)elif sign = "-": print(num1 - num2)elif sign = "*": print(num1*num2)elif sign = "/": print(num1/num2)抱歉，我是 python 新手...
3 回答
MMTTMM
TA貢獻1869條經驗 獲得超4個贊
您的代碼不起作用的原因是因為您只是將兩個數字相乘/除/加/減，而這兩個數字現在聲明為一個字符串。
在 python 中，您不能將字符串作為整數進行加/減/乘/除。您需要將 num1 和 num2 聲明為整數。
num1 = int(input("Enter in your first number"))
num2 = int(input("Enter in your second number"))
sign = input("Enter in the calculator operator you would like")
if sign == "+":
print(num1 + num2)
elif sign == "-":
print(num1 - num2)
elif sign == "*":
print(num1*num2)
elif sign =="/":
print(num1/num2)
偶然的你
TA貢獻1841條經驗 獲得超3個贊
您的代碼中有很多語法錯誤，請查看注釋以了解可以改進的地方，底部有一些閱讀材料！
num1 = int(input("Enter in the first number")) # You need to cast your input to a int, input stores strings.
num2 = int(input("Enter in the second number")) # Same as above, cast as INT
sign = input("Enter in the calculator operator you would like")
# You cannot use `elif` before declaring an `if` statement. Use if first!
if sign == "+": # = will not work, you need to use the == operator to compare values
print(num1 + num2)
elif sign == "-": # = will not work, you need to use the == operator to compare values
print(num1 - num2)
elif sign == "*": # = will not work, you need to use the == operator to compare values
print(num1*num2)
elif sign == "/": # = will not work, you need to use the == operator to compare values
print(num1/num2)
代碼可以很好地適應這些更改，但是您應該閱讀Python 語法和運算符！
大話西游666
TA貢獻1817條經驗 獲得超14個贊
您收到此錯誤是因為默認情況下輸入會給出一個字符串。在使用它之前，您必須將其轉換為 int。
num1 = int(input("Enter in the first number"))
num2 = int(input("Enter in the second number"))
sign = input("Enter in the calculator operator you would like")
if sign == "+":
print(num1 + num2)
elif sign == "-":
print(num1 - num2)
elif sign == "*":
print(num1*num2)
elif sign == "/":
print(num1/num2)
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