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使用變量過濾器對對象數組進行排序

JavaScript

三國紛爭 2022-07-01 16:52:47

我試圖按當月過濾我的對象數組。以動物穿越魚為例const fishData = { "fish_name": "Barreleye", "price": "15,000", "location": "Sea", "shadow_size": "Small", "n_March": true, "n_3": true, }, { "fish_name": "Coelacanth", "price": "15,000", "location": "Sea (Rainy Days)", "shadow_size": "Largest", "n_3": true, }]var today = new Date();var currentMonth = today.getMonth();var fishMonth = `n_ + ${currentMonth}`;console.log(fishMonth);var filteredFish = fishData.filter(function(i) { return i.fishMonth == true;});現在返回，如果我放"n_3"而不是"fishMonth"代碼運行良好。我已經檢查過了"fishMonth"，它確實返回了n_3。什么會阻止這個工作？

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2 回答

牧羊人nacy

TA貢獻1862條經驗獲得超7個贊

您的變量中有不必要的字符fishMonth，它應該是：

var fishMonth = `n_${currentMonth}`;

并且您還想讀取對象的密鑰，因此必須有return i[fishMonth] == true;，請嘗試：

const fishData = [{

"fish_name": "Barreleye",

"price": "15,000",

"location": "Sea",

"shadow_size": "Small",

"n_March": true,

"n_3": true,

{

"fish_name": "Coelacanth",

"price": "15,000",

"location": "Sea (Rainy Days)",

"shadow_size": "Largest",

"n_3": true,

}

]

var today = new Date();

var currentMonth = today.getMonth();

var fishMonth = `n_${currentMonth}`;

var filteredFish = fishData.filter(function(i) {

return i[fishMonth] == true;

});

console.log(filteredFish);

反對回復 2022-07-01

30秒到達戰場

TA貢獻1828條經驗獲得超6個贊

您需要沒有空格的正確鍵值和帶括號+的正確屬性訪問器。

您可以進行更多更改，例如直接從實例中獲取月份并直接返回所需屬性的值。

const

fishData = [{ fish_name: "Barreleye", price: "15,000", location: "Sea", shadow_size: "Small", n_March: true, n_3: true }, { fish_name: "Coelacanth", price: "15,000", location: "Sea (Rainy Days)", shadow_size: "Largest", n_3: true }],

fishMonth = `n_${(new Date).getMonth()}`,

filteredFish = fishData.filter(fish => fish[fishMonth]);

console.log(filteredFish);

最后，您可以更改整個數據結構并將月份作為值添加到對象并使用類似月份屬性的東西。這允許使用與值的簡單比較，而不是使用復合鍵。

const

fishData = [{ fish_name: "Barreleye", price: "15,000", location: "Sea", shadow_size: "Small", n_March: true, month: 3 }, { fish_name: "Coelacanth", price: "15,000", location: "Sea (Rainy Days)", shadow_size: "Largest", month: 3 }],

fishMonth = (new Date).getMonth(),

filteredFish = fishData.filter(({ month }) => month === fishMonth);

console.log(filteredFish);

反對回復 2022-07-01

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使用變量過濾器對對象數組進行排序

使用變量過濾器對對象數組進行排序

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