我有一個字符串、整數和列表的列表，我們稱之為 listAimport astlistA = "['0', '['0', '0']']我想將其轉換為列表預期的結果是['0', ['0', '0']]當我運行以下代碼將其轉換為列表時：listA = ast.literal_eval(listA)它返回一個語法錯誤>`Traceback (most recent call last):  File "e:\Anaconda3\lib\site-packages\IPython\core\interactiveshell.py", line 3326, in run_code    exec(code_obj, self.user_global_ns, self.user_ns)  File "<ipython-input-4-6494c28ce5e6>", line 1, in <module>    literal_eval("['0', '['0', '0']']")  File "e:\Anaconda3\lib\ast.py", line 46, in literal_eval    node_or_string = parse(node_or_string, mode='eval')  File "e:\Anaconda3\lib\ast.py", line 35, in parse    return compile(source, filename, mode, PyCF_ONLY_AST)  File "<unknown>", line 1    ['0', '['0', '0']']             ^SyntaxError: invalid syntax`我哪里出錯了，我該如何解決？另外，我試過了，listA = listA.replace("'", "\')但錯誤是一樣的編輯：（這是形成字符串 listA 的代碼）listA = "['0', '0', 'a']"before = "a"after = ["0", "0"]listA = listA.replace(str(before), str(after))