我有一個raw.txt在下面。ok: [192.168.1.1] => { "OS": "Ubuntu(Core) "}ok: [192.168.1.2] => { "OS": "Ubuntu (Core) " }ok: [192.168.1.3] => { "OS": "CentOS (Core) "}ok: [192.168.1.3] => { "OS":"CentOS (Core) " }ok: [192.168.1.5] => { "OS": "Red Hat(Core) "}ok: [192.168.1.6] => { "OS": "CentOS (Core) " }我的 Python 代碼如下所示如何轉換為可取的輸出f = open(r'raw.txt', 'r')s = f.read()list1 = s.split('\n')ip_list = []os_list = []for i in list1[::3]: ip_list.append(i)for i in list1[1::3]: os_list.append(i)y = [z[10:25] for z in os_list]os_l = [x.strip(' ').replace('"','').replace(' ','') for x in y]ip_l = [z[5:18] for z in ip_list]ip_l_rep = [x.strip(' ').replace(']','') for x in ip_l]{ip_l_rep[n]:os_l[n] for n in range(len(os_l))}我的輸出和預期低于{'192.168.1.1': 'Ubuntu(Core)', '192.168.1.2': 'Ubuntu(Core)', '192.168.1.3': 'CentOS(Core)', '192.168.1.5': 'RedHat(Core)', '192.168.1.6': 'CentOS(Core)'}由于在這個程序中使用了多個操作，我決定在正則表達式的幫助下編寫。我寫了一些偽代碼但沒有成功。喜歡提取\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}.我的代碼的任何增強也很感激
2 回答
慕森王
TA貢獻1777條經驗 獲得超3個贊
您可以使用正則表達式來捕獲介于之間[]和之后的內容"OS": "：
import re
input = """
ok: [192.168.1.1] => {
"OS": "Ubuntu(Core) "
}
ok: [192.168.1.2] => {
"OS": "Ubuntu (Core) "
}
ok: [192.168.1.3] => {
"OS": "CentOS (Core) "
}
ok: [192.168.1.3] => {
"OS":"CentOS (Core) "
}
ok: [192.168.1.5] => {
"OS": "Red Hat(Core) "
}
ok: [192.168.1.6] => {
"OS": "CentOS (Core) "
}
"""
items = re.findall(r'\[(.*?)\].*?"OS": "(.*?)"', input, flags=re.S)
data = dict(items) # only works as you have 2 items (IP, OSTYPE)
print(data)
# output: {'192.168.1.1': 'Ubuntu(Core) ', '192.168.1.2': 'Ubuntu (Core) ', '192.168.1.3': 'Red Hat(Core) ', '192.168.1.6': 'CentOS (Core) '}
猛跑小豬
TA貢獻1858條經驗 獲得超8個贊
這會從引號之間的文本中去除不需要的空間"：
import re
f = open(r'raw.txt', 'r')
text = f.read()
f.close()
pattern = r'\[(.+?)\].+?:\s*"\s*(.+?)\s*"'
result = dict(re.findall(pattern, text, flags=re.DOTALL))
print(result)
# {'192.168.1.1': 'Ubuntu(Core)', '192.168.1.2': 'Ubuntu (Core)', '192.168.1.3': 'CentOS (Core)', '192.168.1.5': 'Red Hat(Core)', '192.168.1.6': 'CentOS (Core)'}
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