我有一本字典，其鍵是字符串，值是數字。我還有另一個字符串列表。如果鍵是字符串列表中的字符串，我想通過刪除所有鍵值對來過濾字典。例如：dict={"good":44,"excellent":33,"wonderful":55}, randomList=["good","amazing","great"]那么該方法應該給出newdict={"excellent":33,"wonderful":55}我想知道是否有一種方法可以使用很少的代碼來做到這一點。有沒有辦法快速做到？
2 回答
至尊寶的傳說
TA貢獻1789條經驗 獲得超10個贊
這段簡單的代碼可以滿足您的需求
oldDict={"good":44,"excellent":33,"wonderful":55}
randomList=["good","amazing","great"]
for word in randomList:
if word in oldDict:
oldDict.pop(word)
print(oldDict)
newDict = oldDict # Optional: If you want to assign it to a new dictionary
# But either way this code does what you want in place
qq_遁去的一_1
TA貢獻1725條經驗 獲得超8個贊
遍歷字典并刪除不在列表中的鍵值對：
d = {'foo': 0, 'bar': 1, 'foobar': 2}
list_of_str = ['foo', 'bang']
{k:v for k, v in d.items() if k not in list_of_str}
輸出：
Out[34]: {'bar': 1, 'foobar': 2}
或者如果你list_of_str的更小，這會更快：
d = {'foo': 0, 'bar': 1, 'foobar': 2}
list_of_str = ['foo', 'bang']
for s in list_of_str:
try:
del d[s]
except KeyError:
pass
輸出：
Out[41]: {'bar': 1, 'foobar': 2}
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