題目描述在計算機系統的時間顯示上,通常以hh:mm:ss格式來顯示,即時:分:秒,每段均以兩個數位顯示,如12:02:59,表示12時2分59秒?,F給出兩個這樣格式的時間,請計算出它們的時間差,并以該格式顯示出來。輸入格式共兩行,每行均為按hh:mm:ss格式的時間信息。輸出格式一行,按hh:mm:ss 格式輸出時間差。樣例輸入00:00:0100:01:00樣例輸出00:00:59數據規模
2 回答
胡子哥哥
TA貢獻1825條經驗 獲得超6個贊
估計這道題不讓用DateTime的相關函數,否則太簡單了。 下面的例子,從校驗用戶的輸入,直到計算時間差,都是用系統的其他函數(非datetime相關),有效時間的范圍是:00:00:00~24:00:00 ,可以個位輸出,例: 0:1:2. --- 為了對比,給出了使用TDateTime相關函數及不使用的方法。
program time_difference;uses strutils, sysutils;type //方法一: 使用TDateTime function getTimeDiff(const stime1 : string; const stime2 : string; var sdiff: string) : Boolean; var dt1, dt2, dtdiff: TDateTime; begin try dt1 := StrToDateTime(stime1); dt2 := StrToDateTime(stime2); dtdiff := dt1 - dt2; DateTimeToString(sdiff, 'hh:mm:ss', dtdiff); except on E:EConvertError do exit(false); end; getTimeDiff := true; end; //方法二: 不使用TDateTime function getTimeDiff_2(const stime1 : string; const stime2 : string; var sdiff: string) : Boolean; var time_1, time_2, time_diff : longint; t_hour, t_minute, t_second : longint; begin if not getTimeInSeconds(stime1, time_1) then exit(false); if not getTimeInSeconds(stime2, time_2) then exit(false); time_diff := time_1 - time_2; if time_diff < 0 then time_diff := -time_diff; t_hour := time_diff div 3600; t_minute := time_diff mod 3600 div 60; t_second := time_diff - t_hour * 3600 - t_minute * 60; sdiff := Format('%.2d:%.2d:%.2d', [t_hour, t_minute, t_second]); exit(true); end; //方法二用到的函數 function getTimeInSeconds(const stime : string; var time_in_seconds : longint) : Boolean; var s_hh, s_mm, s_ss : string; hour, minute, second, errcode : integer; begin s_hh := ExtractDelimited(1, stime, [':']); s_mm := ExtractDelimited(2, stime, [':']); s_ss := ExtractDelimited(3, stime, [':']); Val(s_hh, hour, errcode); if errcode <> 0 then exit(false); Val(s_mm, minute, errcode); if errcode <> 0 then exit(false); Val(s_ss, second, errcode); if errcode <> 0 then exit(false); if not (hour in [0..24]) then exit (false); if not (minute in [0..59]) then exit (false); if not (second in [0..59]) then exit (false); if (hour = 24) and ( (minute <> 0) or (second <> 0) ) then exit(false); time_in_seconds := hour * 3600 + minute * 60 + second; exit(true); end;//主程序var stime1, stime2 : String; //t_sec_1, t_sec_2 : Longint; stdiff : string;begin writeln ('Input two times (hh:mm:ss):'); readln(stime1); readln(stime2); //方法一 if getTimeDiff(stime1, stime2, stdiff) then writeln(stdiff) else writeln('Error happened.'); //方法二 if getTimeDiff_2(stime1, stime2, stdiff) then writeln('Diff. ', stdiff) else writeln('Error happened.'); end. |
運行:
Input two times (hh:mm:ss):12:34:5623:45:001. 11:10:042. 11:10:04 |
炎炎設計
TA貢獻1808條經驗 獲得超4個贊
const
m=300;
var i:byte;
a,b,s:integer;
begin
b:=0;s:=0;
for i:=1 to 12 do
begin
read(a);
if a>m+b then
begin
writeln(-i);
exit;
end;
if m+b-a>=100
then
begin
s:=s+100*((m+b-a) div 100);
b:=(m+b-a)mod 100;
end
else b:=m+b-a;
end;
writeln(1.2*s+b:0:0);
end.
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