2 回答

TA貢獻1906條經驗 獲得超10個贊
嘗試在 while 條件中使用它
Scanner inputUserName = new Scanner(System.in);
String userNameInput = inputUserName.nextLine();
while (!userNameInput.contains("@"))
{
System.out.println("\nPlease enter a valid user name!");
userNameInput = inputUserName.nextLine();
}
System.out.println("Success");

TA貢獻1831條經驗 獲得超10個贊
您可以通過使用 while 循環來做到這一點 -
Scanner inputUserName = new Scanner(System.in);
String userName = "User Name: ";
System.out.println(userName);
String userNameInput = inputUserName.nextLine();
while (!userNameInput.contains("@"))
{
System.out.println("\nPlease enter a valid user name!");
System.out.println(userName);
userNameInput = inputUserName.nextLine()
}
}
System.out.println("Shap");
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