我想通過 json 輸入在 listview 上顯示兩個數據。所有代碼都來自互聯網，我得到了錯誤。我沒有清晰的邏輯來理解代碼的含義。請給我建議并更改我的代碼。 private void displayArrayList(String jsonStr){ String[] from = {"eventName", "date"}; int[] to = {R.id.eventName, R.id.date}; SimpleAdapter simpleAdapter = new SimpleAdapter ( getActivity(),convertToＷordArrayList(jsonStr), R.layout.listview_layout,from,to); simpleAdapter.notifyDataSetChanged(); listView.setAdapter(simpleAdapter); } private ArrayList<HashMap<String, ActivityInfo>> convertToＷordArrayList(String jsonStr){ JSONObject jsonObject ; ArrayList<HashMap<String, ActivityInfo>> arrayList = new ArrayList<HashMap<String, ActivityInfo>>(); try{ jsonObject = new JSONObject(jsonStr); JSONArray jsonArray=jsonObject.getJSONArray("article"); for (int i=0;i<jsonArray.length();i++){ JSONObject jsonObjRow=jsonArray.getJSONObject(i); ActivityInfo activityInfo =new ActivityInfo(); activityInfo.eventName = jsonObjRow.getString("eventName"); activityInfo.date = jsonObjRow.getString("date"); HashMap<String, String> map= new HashMap<String, ActivityInfo>(); map.put("eventName", activityInfo.eventName ); map.put("date", activityInfo.date); JSONArray jsonArray2=jsonObjRow.getJSONArray("content"); for (int j=0;j<jsonArray2.length();j++) { JSONObject jsonObjRow2 = jsonArray2.getJSONObject(j); activityInfo.review = jsonObjRow2.getString("review"); } arrayList.add(activityInfo); } }catch (JSONException e){ e.printStackTrace(); } return arrayList; }
2 回答
胡子哥哥
TA貢獻1825條經驗 獲得超6個贊
這是你的模型類..
ActivityInfo.java
public class ActivityInfo implements Serializable {
String eventName;
String date;
public void setEventName(String eventName){
this.eventName = eventName ;
}
public String getEventName(){
return this.eventName;
}
public void setDate(String date){
this.date = date;
}
public String getDate(){
return date;
}
}
這將是您最終的無錯誤代碼..
private void displayArrayList(String jsonStr){
String[] from = {"eventName", "date"};
int[] to = {R.id.eventName, R.id.date};
SimpleAdapter simpleAdapter = new SimpleAdapter (
getActivity(),convertToＷordArrayList(jsonStr), R.layout.listview_layout,from,to);
simpleAdapter.notifyDataSetChanged();
listView.setAdapter(simpleAdapter);
}
private ArrayList<HashMap<String,String>> convertToＷordArrayList(String jsonStr){
JSONObject jsonObject;
ArrayList<HashMap<String,String>> arrayList = new ArrayList();
try{
jsonObject = new JSONObject(jsonStr);
JSONArray jsonArray=jsonObject.getJSONArray("article");
for (int i=0;i<jsonArray.length();i++){
JSONObject jsonObjRow=jsonArray.getJSONObject(i);
HashMap<String,String> hashMap=new HashMap<>();//create a hashmap to store the data in key value pair
hashMap.put("eventName",jsonObjRow.getString("eventName"));
hashMap.put("date",jsonObjRow.getString("date"));
JSONArray jsonArray2=jsonObjRow.getJSONArray("content");
/*If you want to get Content Reviews from Json, you need to make another attributes like Content in ActivityInfo Class*/
arrayList.add(hashmap);
}
}catch (JSONException e){
e.printStackTrace();
}
return arrayList;
}
HUX布斯
TA貢獻1876條經驗 獲得超6個贊
我完全這樣做：
public class menuCreation()
{
public string Category { get; set; }
public string ItemName { get; set; }
public string Price { get; set; }
public string FileName { get; set; }
public menuCreation[] Arr { get; set; }
Stream responseStream = response.GetResponseStream();
StreamReader reader = new StreamReader(responseStream);
string json = (reader.ReadToEnd());
List<menuCreation> items = JsonConvert.DeserializeObject<List<menuCreation>>(json);
Arr = items.ToArray();
}
menuCreation mc = new menuCreation();
foreach (var item in mc.Arr)
{
PictureBox pb = new PictureBox();
pb.Tag = item.ItemName;
pb.Name = item.Price;
}
您可以看到，我使用類對象到達 itemName。因此，您可以使用此方法添加列表視圖。
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