我不懂井字游戲。我剛開始學習 Android 并學習了一門很容易開始的課程，但現在我被困在這個游戲中。請幫我。我被困在這段代碼中。誰能解釋一下那里發生了什么？for (int[] columnWinner : winner) { if (playerChoices[columnWinner[0]] == playerChoices[columnWinner[1]] && playerChoices[columnWinner[1]] == playerChoices[columnWinner[2]] && playerChoices[columnWinner[0]] != Player.NO) { Toast.makeText(getApplicationContext(), "We have Winner", Toast.LENGTH_LONG).show(); } }這是完整的代碼，它運行良好，沒有任何錯誤。Player currentPlayer = Player.ONE;Player[] playerChoices = new Player[9];int[][] winner = {{0, 1, 2}, {3, 4, 5}, {6, 7, 8}, {0, 3, 6}, {1, 4, 7}, {2, 5, 8}, {0, 4, 8}, {2, 4, 6}};@Overrideprotected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); playerChoices[0] = Player.NO; playerChoices[1] = Player.NO; playerChoices[2] = Player.NO; playerChoices[3] = Player.NO; playerChoices[4] = Player.NO; playerChoices[5] = Player.NO; playerChoices[6] = Player.NO; playerChoices[7] = Player.NO; playerChoices[8] = Player.NO;}public void imageViewIsTapped(View imageView) { ImageView tappedImage = (ImageView) imageView; tappedImage.setTranslationX(-2000); int tiTag = Integer.parseInt(tappedImage.getTag().toString()); playerChoices[tiTag] = currentPlayer; if (currentPlayer == Player.ONE) { tappedImage.setImageResource(R.drawable.tiger); currentPlayer = Player.TWO; } else if (currentPlayer == Player.TWO) { tappedImage.setImageResource(R.drawable.lion); currentPlayer = Player.ONE; } for (int[] columnWinner : winner) {}enum Player { ONE, TWO, NO}}
井字游戲邏輯
慕婉清6462132
2022-06-15 10:44:53
