假設我有這個列表：names = ['your name', 'the name', 'his name', 'her name', 'their name', 'employer name', "employer's name", "father's name", "mother's name", "maiden name", "son's name", "daughter's name", "brother's name", "sister's name"]假設我有這段文字：text = "What is your name? Well, uh it's John Smith. Thanks for asking. Anyway, I'd doing well."如何使用正則表達式在文本中查找列表名稱的每個元素，并立即用“[name]”替換元素之后的文本塊（例如，長度為 50）。所以我的輸出是：text = "What is your name [name] Anyway, I'd doing well."到目前為止，我在下面有這段代碼，但它只用“[name]”替換了元素，而不是元素后面的實際文本。def my_replace3(match): match = match.group() return " [name] "def no_name(text): names = ['your name', 'the name', 'his name', 'her name', 'their name', 'employer name', "employer's name", "father's name", "mother's name", "maiden name", "son's name", "daughter's name", "brother's name", "sister's name"] regex = re.compile(r'\b(' + '|'.join(names) + r')\b', re.IGNORECASE) text = re.sub(regex, my_replace3, text) return text我不是一個偉大的正則表達式專家，所以你的幫助將不勝感激。
1 回答
三國紛爭
TA貢獻1804條經驗 獲得超7個贊
如果要在匹配后替換 50 個字符，請添加.{50}到正則表達式。
然后在替換字符串中使用反向引用將匹配的字符串復制到替換。
def no_name(text):
names = ['your name', 'the name', 'his name', 'her name', 'their name', 'employer name', "employer's name", "father's name",
"mother's name", "maiden name", "son's name", "daughter's name", "brother's name", "sister's name"]
regex = re.compile(r'\b(' + '|'.join(map(re.escape, names)) + r')\b.{50}', re.IGNORECASE)
text = re.sub(regex, r'\1 [name]', text)
return text
您還應該re.escape()在將應該完全匹配的字符串插入到正則表達式中時使用，以防它們中的任何一個包含正則表達式運算符。
添加回答
舉報
0/150
提交
取消