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NodeJS MongoDB崩潰“參數必須是對象”

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狐的傳說 2022-06-09 16:25:56

當我運行我的服務器并將表單昵稱發送到數據庫時，我的程序崩潰了！它告訴我這是因為它需要成為一個對象。如果我將 req.body.pickname 更改為 req.body ，它運行良好，但是我需要保存的數據不會被保存。有沒有辦法把它變成一個對象，或者讓它工作？服務器.jsvar mongoose = require("mongoose");var bodyParser = require("body-parser");var express = require("express");var app = express();app.use(bodyParser.json());app.use(bodyParser.urlencoded({extended: true}));var PORT = 45050;app.use("/", express.static(__dirname));mongoose.Promise = global.Promise;mongoose.connect("mongodb://localhost/thisworks", { useNewUrlParser: true});var gameSchema = new mongoose.Schema({ nickname: String});var User = mongoose.model("wowww", gameSchema);app.post("/addname", (req, res) =>{ var playerNickname = new User(req.body.pickname); playerNickname.save() .then(item => { console.log("nickname created " + req.body.pickname); }) .catch(err => { res.status(400).send("unable to save to database"); console.log("error baby!"); });});app.listen(PORT, function () { console.log("server is up and running using port " + PORT)});索引.html<form method="post" action="/addname"> <h1 class="center-align"> <input id="pickName" class="center-align" type='text' name='pickname' placeholder='Nickname' required> </h1> <h1 class='center-align'><input id='rea2dy' value=" Ready >" type='submit'></h1> </form>如果有幫助，這就是我得到的錯誤。

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2 回答

慕妹3146593

TA貢獻1820條經驗獲得超9個贊

const express = require('express');

var mongoose = require('mongoose');

const bodyParser = require('body-parser');

var morgan = require('morgan');

var cors = require('cors')

const app = express();

// CORS Middleware

app.use(cors());

// Logger Middleware

app.use(morgan('dev'));

// Bodyparser Middleware

app.use(bodyParser.json());

const MongoClient = require('mongodb').MongoClient;

const uri = "uri";

const client = new MongoClient(uri, { useNewUrlParser: true, useUnifiedTopology: true });

client.connect(err => {

console.log('MongoDB Connected...')

const collection = client.db("dbname").collection("collectionname");

app.post('/name', (req, res) => {

collection. insertOne({ name: req.body.name })

res.send("data added")

});

const port = process.env.PORT || 5000;

app.listen(port, function () {

console.log(`Example app listening on port ${port}`);

});

反對回復 2022-06-09

慕后森

TA貢獻1802條經驗獲得超5個贊

這似乎可行，以防將來有人遇到同樣的問題。我使用 mongodb 而不是 mongoose 要求

但是如果你有一個適用于貓鼬的解決方案，請發布它:)

var mongoose = require("mongoose");

var bodyParser = require("body-parser");

var express = require("express");

var app = express();

var PORT = 3332;

app.use("/", express.static(__dirname));

app.use(bodyParser.json());

app.use(bodyParser.urlencoded({extended: true}));

mongoose.connect("mongodb://localhost/thisworks", {

useNewUrlParser: true

});

var db = mongoose.connection;

db.once('open', function(cb) {

console.log("connection established");

})

app.post("/addname", (req, res) =>{

var name = req.body;

var data = {

"nickname": name

}

db.collection('wowww').insertOne(data, function(err, coll) {

if(err) throw err;

console.log('rec estab');

});

app.listen(PORT, function () {

console.log("server is up and running using port " + PORT)

});

反對回復 2022-06-09

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NodeJS MongoDB崩潰“參數必須是對象”

NodeJS MongoDB崩潰“參數必須是對象”

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