2 回答

TA貢獻1866條經驗 獲得超5個贊
function handleResponse(obj) {
const container = document.getElementById("container")
obj.items.forEach((rec, index) => {
let singleBookCover =
rec.volumeInfo.imageLinks && rec.volumeInfo.imageLinks.smallThumbnail;
let singleBookTitle = rec.volumeInfo.title;
let singleBookAuthor = rec.volumeInfo.authors[0];
let book = document.createElement("div");
book.className = "book"
book.innerHTML = `
<div><h1>${singleBookTitle}<h1>
<p>${singleBookAuthor}</p>
<img src="${singleBookCover}"></img>
</div>
`
content.appendChild(book)
});
}
<div id="content" class="books">
</div>
<script src="https://www.googleapis.com/books/v1/volumes?q=clean+code&callback=handleResponse"></script>

TA貢獻1772條經驗 獲得超8個贊
干凈的答案 - 你應該使用document.appendChild(child)而不是 innerHTML 方法。
此外,最近添加的 js 方法很少,可以幫助您操作大型 JSON 對象 - map、reduce、filter。
我添加了示例,如何將原始對象清理為更小的數組,并將該數組中的項目插入 html-page。
function demo (obj) {
// getting all items from object
const book = Object.keys(obj).map(item => obj['items']).reduce(
(acc,rec, id, array) => {
// getting Cover, Title, Author from each item
let singleBookCover = rec[id].volumeInfo.imageLinks.thumbnail;
let singleBookTitle = rec[id].volumeInfo.title;
let singleBookAuthor = rec[id].volumeInfo.authors[0];
// Creating new array only with Cover, Title, Author
return [...acc, {singleBookCover, singleBookTitle, singleBookAuthor}]
},
[]
).forEach( item => {
// For each item on our array, we creating h1
let title = document.createElement('h1');
title.textContent = `${item.singleBookTitle} by ${item.singleBookAuthor}`;
// img
let img = document.createElement('img');
img.src = item.singleBookCover;
img.alt = `${item.singleBookTitle} by ${item.singleBookAuthor}`;
// and div wrapper
let container = document.createElement('div');
// adding our child elements to wrapper
container.appendChild(title).appendChild(img);
// adding our wrapper to body
document.body.appendChild(container);
})
return book
}
希望我的回答對你有幫助)
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