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JavaScript / typescript：無法重新生成對象

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一只名叫tom的貓 2022-06-09 10:58:01

我有一個如下指定的對象：{"player settings": [ { "id": 1, "labelName": "site language", "labelValue": [ { "id": 1, "languageName": "ARABIC", "language": "????", "languageCode": "AE" }, { "id": 2, "languageName": "CHINESE", "language": "你的語言", "languageCode": "ZH" }, ], "dataType": "DD", "selectedData": "2" }, { "id": 2, "labelName": "subtitle language", "labelValue": [ { "id": 1, "languageName": "ARABIC", "language": "????", "languageCode": "AE" }, { "id": 2, "languageName": "CHINESE", "language": "你的語言", "languageCode": "ZH" }, ], "dataType": "DD", "selectedData": "1" }, ]},{ "channel": [ { "id": 11, "labelName": "channel label", "dataType": "TX", "selectedData": "jhfh" } ]},{ "others": [ { "id": 16, "labelName": "others label", "dataType": "TX", "selectedData": "dhgdhg" } ]}如何在以下條件下修改和重新生成對象：if dataType=== 'DD' 然后轉換selectedData成數字。我寫了下面的代碼，但卡在這里：for (var j = 0; j < this.myobject.length; j++){ this.myobject.forEach(obj => { console.log(obj) });}

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3 回答

蠱毒傳說

TA貢獻1895條經驗獲得超3個贊

您可以使用for..in

let data = {"player settings": [{"id": 1,"labelName": "site language","labelValue": [{"id": 1,"languageName": "ARABIC","language": "????","languageCode": "AE"},{"id": 2,"languageName": "CHINESE","language": "你的語言","languageCode":"ZH"},],"dataType": "DD","selectedData": "2"},],"player settings2": [{"id": 1,"labelName": "site language","labelValue": [{"id": 1,"languageName": "ARABIC","language": "????","languageCode": "AE"},{"id": 2,"languageName": "CHINESE","language": "你的語言","languageCode":"ZH"},],"dataType": "NO DD","selectedData": "2"},]}

for (let key in data) {

data[key].forEach(obj => {

if (obj.dataType === "DD") {

obj.selectedData = +(obj.selectedData || 0)

}

})

}

console.log(data)

不變的方法

let newObj = {}

for (let key in data) {

newObj[key] = data[key]

data[key].forEach(obj => {

if (obj.dataType === "DD") {

newObj.selectedData = +(obj.selectedData || 0)

}

})

}

console.log(newObj)

反對回復 2022-06-09

臨摹微笑

TA貢獻1982條經驗獲得超2個贊

我們可以在主 obj 上使用過濾器，然后繼續修改對象。

function modifyDataToNumber(){

let myObject = jsonObj['player settings'];

let ddMyObject = myObject.filter((row)=>(row["dataType"]==="DD"));

console.log(ddMyObject[0]["selectedData"]);

ddMyObject.forEach((row,index)=>{

ddMyObject[index]["selectedData"] = +ddMyObject[index]["selectedData"];

})

console.log(jsonObj);

}

modifyDataToNumber();

反對回復 2022-06-09

慕標琳琳

TA貢獻1830條經驗獲得超9個贊

既然您說“重新生成”，我假設您想要一種不可變的方法（即，生成具有所需更改的數據副本，而不是更改原始對象）。

為此，您可以使用擴展語法和Array#map：

let convertSetting = setting => ({

...setting,

selectedData: setting.dataType === "DD"

? parseInt(setting.selectedData)

: setting.selectedData

});

let convert = x => ({

...x,

["player settings"]: x["player settings"].map(convertSetting)

});

然后，您可以將該功能用作convert(yourOriginalObject).

反對回復 2022-06-09

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JavaScript / typescript：無法重新生成對象

JavaScript / typescript：無法重新生成對象

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