我之前有一個功能版本，它使用了較少的唯一變量和第一個變量的更多實例，但是在添加了兩個與第一個變量相關的變量之后，我的代碼出現了一個錯誤，表明我需要初始化我的變量“numbList”。理想情況下，我想在每個新行之后簡單地更新“numbList”的值，然后更新“numbSquare”和“numbCube”的值。到目前為止，我還沒有多少運氣。public class Assignment2BPart2 { public static void main(String[] args) { int numbList; int numbSquare; int numbCube; numbSquare = numbList * numbList; numbCube = numbSquare * numbList; System.out.println("The following is a table of values, showing numbers 0 - 10 and their squares and cubes."); System.out.printf("%s%s%s%n", "Number ", "Square ", "Cube"); System.out.printf("%d \t %d \t %d%n", numbList = 0, numbSquare, numbCube); System.out.printf("%d \t %d \t %d%n", numbList = 1, numbSquare, numbCube); System.out.printf("%d \t %d \t %d%n", numbList = 2, numbSquare, numbCube); System.out.printf("%d \t %d \t %d%n", numbList = 3, numbSquare, numbCube); System.out.printf("%d \t %d \t %d%n", numbList = 4, numbSquare, numbCube); System.out.printf("%d \t %d \t %d%n", numbList = 5, numbSquare, numbCube); System.out.printf("%d \t %d \t %d%n", numbList = 6, numbSquare, numbCube); System.out.printf("%d \t %d \t %d%n", numbList = 7, numbSquare, numbCube); System.out.printf("%d \t %d \t %d%n", numbList = 8, numbSquare, numbCube); System.out.printf("%d \t %d \t %d%n", numbList = 9, numbSquare, numbCube); System.out.printf("%d \t %d \t %d%n", numbList = 10, numbSquare, numbCube); }}預期結果將是一個帶有標題閱讀的 3 列表數方立方第 1 列的其余部分是值 0-10，第 2 列是這些數字的平方，第 3 列是這些數字的立方。到目前為止，我無法在此迭代中運行代碼。
3 回答
紅顏莎娜
TA貢獻1842條經驗 獲得超13個贊
實現這樣重復的通常方法是使用for循環：
System.out.println("The following is a table of values, showing numbers 0 - 10 and their squares and cubes.");
System.out.printf("%s%s%s%n", "Number ", "Square ", "Cube");
for (int num = 0; num <= 10; num++) {
System.out.printf("%d \t %d \t %d%n", num, num * num, num * num * num);
}
白衣非少年
TA貢獻1155條經驗 獲得超0個贊
您正在尋找的解決方案是如何使代碼和變量可重用。一種方法是使用函數，盡管您可能還沒有學習到這一點。然后，您將使用 for 循環將數字 1 到 10 輸入到您的函數中以獲得所需的輸出。
public static int NumberSquared(int number)
{
return number*number;
}
public static int NumberCubed(int number)
{
return number*number*number;
}
public static void main(String[] args)
{
for(int i=0; i <= 10; i++)
{
System.out.println("Number " + i + " Square: " + NumberSquared(i) + " Cube: " + NumberCubed(i));
}
}
眼眸繁星
TA貢獻1873條經驗 獲得超9個贊
邏輯是錯誤的，你必須在更新之后計算平方和立方體numbList，所以你必須使用任何循環或遞歸來做到這一點，但我更喜歡有兩種方法返回 int 值，一個用于計算平方，另一個用于立方體
public class NewMain {
public static void main(String[] args) {
int numbList = 0;
System.out.println("The following is a table of values, showing numbers 0 - 10 and their squares and cubes.");
System.out.printf("%s%s%s%n", "Number ", "Square ", "Cube");
//
System.out.printf("%d \t %d \t %d%n", numbList = 0, squareOfNumber(numbList), cubeOfNumber(numbList));
System.out.printf("%d \t %d \t %d%n", numbList = 1, squareOfNumber(numbList), cubeOfNumber(numbList));
System.out.printf("%d \t %d \t %d%n", numbList = 2, squareOfNumber(numbList), cubeOfNumber(numbList));
System.out.printf("%d \t %d \t %d%n", numbList = 3, squareOfNumber(numbList), cubeOfNumber(numbList));
System.out.printf("%d \t %d \t %d%n", numbList = 4, squareOfNumber(numbList), cubeOfNumber(numbList));
System.out.printf("%d \t %d \t %d%n", numbList = 5, squareOfNumber(numbList), cubeOfNumber(numbList));
System.out.printf("%d \t %d \t %d%n", numbList = 6, squareOfNumber(numbList), cubeOfNumber(numbList));
System.out.printf("%d \t %d \t %d%n", numbList = 7, squareOfNumber(numbList), cubeOfNumber(numbList));
System.out.printf("%d \t %d \t %d%n", numbList = 8, squareOfNumber(numbList), cubeOfNumber(numbList));
System.out.printf("%d \t %d \t %d%n", numbList = 9, squareOfNumber(numbList), cubeOfNumber(numbList));
System.out.printf("%d \t %d \t %d%n", numbList = 10, squareOfNumber(numbList), cubeOfNumber(numbList));
}
public static int squareOfNumber(int num) {
return num*num;
}
public static int cubeOfNumber(int num) {
return num*num*num;
}
}
for循環你可以應用上面相同的邏輯
for(int i=0; i<=10; i++) {
System.out.printf("%d \t %d \t %d%n", i, i*i, i*i*i);
}
你也可以使用Math.pow()
nt intResult = (int) Math.pow(2, 3);
該方法將 2 提高到 3 的冪并返回結果
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