我想將 json api 標準文檔簡化為駱駝版本。我能夠制作一個camelCase對象和單個原始類型鍵。我希望所需的輸出是每個鍵camelCase。所以在上面的例子中first-name會變成firstName，snake-case會變成snakeCase。我面臨的問題是如何使用我現在使用的相同遞歸調用來處理對象數組。import _ from "lodash";const data = {  id: 1,  type: "user",  links: { self: "/movies/1" },  meta: { "is-saved": false },  "first-name": "Foo",  "last-name": "Bar",  locations: ["SF"],  actors: [    { id: 1, type: "actor", name: "John", age: 80 },    { id: 2, type: "actor", name: "Jenn", age: 40 }  ],  awards: [    {      id: 4,      type: "Oscar",      links: ["asd"],      meta: ["bar"],      category: "Best director",      'snake_case': 'key should be snakeCase'    }  ],  name: { id: 1, type: "name", title: "Stargate" }};const needsCamelCase = str => {  return str.indexOf("-") > -1 || str.indexOf("_") > -1;};const strToCamelCase = function(str) {  return str.replace(/^([A-Z])|[\s-_](\w)/g, function(match, p1, p2, offset) {    if (p2) return p2.toUpperCase();    return p1.toLowerCase();  });};const toCamelCase = obj => {  Object.keys(obj).forEach(key => {    if (_.isPlainObject(obj[key])) {      return toCamelCase(obj[key]);    }    if (_.isArray(obj[key])) {      // console.log(obj[key]);      obj[key].forEach(element => {        console.log(element);      });      //obj[key].foreach(element_ =>  toCamelCase);    }    if (needsCamelCase(key)) {      obj[strToCamelCase(key)] = obj[key];      delete obj[key];    }  });  return obj;};// toCamelCase(data);console.log(toCamelCase(data));這是一個代碼框： https ://codesandbox.io/s/javascript-l842u