我是 python 3 的新手，并試圖從包含消息中字符串和字節的字節數組中提取消息。我無法從解碼的字節數組中提取字節消息。首先，我解碼字節數組。然后我對解碼后的數組進行拆分。我在拆分數組時得到字符串值。我嘗試使用bytes(v) for v in rest.split()函數嘗試獲取字節數組，然后對其進行解碼，但無法。# The message chunk:chunk = b"1568077849\n522\nb'l5:d4:auth53:\xc3\x99\xc3\xac\x1fH\xc2\xa3ei6eli1eee'\n"# I split the chunk into sub categories for further processing:_, size, rest = (chunk.decode("utf-8")).split('\n', 2)# _ contains "1568077849"# size contains "522" # rest contains "b'l5:d4:auth53:\xc3\x99\xc3\xac\x1fH\xc2\xa3ei6eli1eee'"我應該能夠解碼其余變量（rest.decode（“utf-8”）），但由于它被存儲為字符串，我很難弄清楚如何將其轉換為字節和然后解碼值。預期結果：l5:d4:auth53:ùìH￡ei6eli1eee
2 回答
嚕嚕噠
TA貢獻1784條經驗 獲得超7個贊
這將打印您的最終結果：
chunk = b"1568077849\n522\nb'l5:d4:auth53:\xc3\x99\xc3\xac\x1fH\xc2\xa3ei6eli1eee'\n"
l1 = chunk.decode('utf-8').split()[2:] # Initial decode
# slice out the embedded byte string "b' '" characters
l1_string = ''.join([x[:-2] if x[0] != 'b' else x[2:] for x in l1])
l1_bytes = l1_string.encode('utf-8')
l1_final = l1_bytes.decode('utf-8')
print('Results')
print(f'l1_string is {l1_string}')
print(f'l1_bytes is {l1_bytes}')
print(f'l1_final is {l1_final}')
Results
l1_string is l5:d4:auth53:ùìH￡ei6eli1ee
l1_bytes is b'l5:d4:auth53:\xc3\x99\xc3\xacH\xc2\xa3ei6eli1ee'
l1_final is l5:d4:auth53:ùìH￡ei6eli1ee
慕絲7291255
TA貢獻1859條經驗 獲得超6個贊
我能夠通過這種方式獲得預期的輸出：
_, size, rest = (chunk.decode("utf-8")).split('\n', 2)
rest = bytes(rest.replace("b'", "").replace("'", ""), "utf-8").decode("unicode_escape")
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