我有問題的代碼（最小的可重現示例）：import ( "fmt" "github.com/aws/aws-sdk-go/aws" "github.com/aws/aws-sdk-go/aws/session" "github.com/aws/aws-sdk-go/service/dynamodb" "github.com/aws/aws-sdk-go/service/dynamodb/expression")const ( tableName = "myTable")var ( sess = session.Must(session.NewSession()) dynamodbClient = dynamodb.New(sess))func main() { update := expression.Set( expression.Name("mymap.vitaly.zdanevich"), expression.Value(true), ) expr, _ := expression.NewBuilder().WithUpdate(update).Build() updateItemInput := dynamodb.UpdateItemInput{ TableName: aws.String(tableName), Key: map[string]*dynamodb.AttributeValue{ "pk": { S: aws.String("test"), }, }, UpdateExpression: expr.Update(), ExpressionAttributeNames: expr.Names(), ExpressionAttributeValues: expr.Values(), } fmt.Printf("%#v\n", updateItemInput) dynamodbClient.UpdateItem(&updateItemInput)}結果更新項目輸入：{ ExpressionAttributeNames: { #0: "mymap", #1: "vitaly", #2: "zdanevich" }, ExpressionAttributeValues: { :0: { BOOL: true } }, Key: { pk: { S: "test" }, sk: { S: "test" } }, TableName: "myTable", UpdateExpression: "SET #0.#1.#2 = :0\n"}是的，我知道 dot 用于訪問內部地圖值，但在這種情況下最好的策略是什么？我目前的解決方案：expression.Name("mymap."+strings.Replace(username, ".", "_", -1))
1 回答
慕工程0101907
TA貢獻1887條經驗 獲得超5個贊
AWS 可以選擇使用表達式屬性名稱 ( Ref ) 來處理這種情況。但是在 aws go 庫中，Expression BuilderExpressionAttributeNames通過Name按點和第三個括號拆分來創建。您可以嘗試不使用表達式生成器。
updateItemInput := dynamodb.UpdateItemInput{
TableName: aws.String(tableName),
Key: map[string]*dynamodb.AttributeValue{
"pk": {
S: aws.String("test"),
},
},
UpdateExpression: aws.String("SET #0.#1 = :0"),
ExpressionAttributeNames: map[string]*string {
"#0": aws.String("mymap"),
"#1": aws.String("vitaly.zdanevich"),
},
ExpressionAttributeValues: map[string]*dynamodb.AttributeValue{
":0": {
BOOL: aws.Bool(true),
},
},
}
fmt.Printf("%#v\n", updateItemInput)
dynamodbClient.UpdateItem(&updateItemInput)
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