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如何確保選定的選項值與隨機變量方程的生成值相匹配

JavaScript

九州編程 2022-05-22 15:54:24

有沒有一種方法可以確保所選值與帶有隨機變量的方程的生成值相匹配，如圖底部所示。存儲數據的對象 var STIIndexYearly = [ { year: 1988, price: 1133.30 }, ... { year: 2019, price: 3153.73 }, ]這是生成值的代碼 var max = 31 var min = 0 var randomone = Math.floor(Math.random() * (max - min)) + min; var randomtwo = Math.floor(Math.random() * (max - randomone + 1)) + randomone + 1; var equationpart1 = ((STIIndexYearly[randomtwo].price / STIIndexYearly[randomone].price)); var equationpart2 = (("1" / (STIIndexYearly[randomtwo].year - STIIndexYearly[randomone].year))); var answer = (Math.pow(equationpart1, equationpart2) - 1)```

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胡子哥哥

TA貢獻1825條經驗獲得超6個贊

我通過使用 for 循環解決了它，一次又一次地重復計算，直到生成的值與選定的選項值匹配。

var Yearly = $("#YearlyAmount").val()

var Age = $("#AgeSlider").val()

$("#form").on('change', function () {

var LumpSum = $("#LumpSumAmount").val()

var Yearly = $("#YearlyAmount").val()

var Age = $("#AgeSlider").val()

var Years = 100 - Age

var Capital = parseFloat(LumpSum) + parseFloat(Yearly) * parseFloat(Years)

$("#info").html("Capital: " + Capital);

console.log(Capital)

});

$("#calculator").click(function () {

var max = 31

var min = 0

var x = document.getElementById("SelectedCompoundInterest").value;

var duration = document.getElementById("SelectedDuration").value;

var invested = document.getElementById("InvestedAmount").value;

var limit = max - duration

console.log(age);

var min_x = parseFloat(x) - 0.025;

var max_x = parseFloat(x) + 0.025;

var randomone = Math.floor(Math.random() * (limit - min)) + min;

var randomtwo = randomone + parseFloat(duration);

var difference = randomtwo - randomone

console.log(randomone, randomtwo)

var answer;

var a = 0

while (true) {

if ((answer >= min_x && answer < max_x && difference == duration) || a >= 10000)

break;

var difference = randomtwo - randomone

var randomone = Math.floor(Math.random() * (limit - min)) + min;

var randomtwo = randomone + parseFloat(duration);

console.log('a: ' + a + ' ans: ' + answer + " min: " + min_x + " max: " + max_x);

var equationpart1 = ((STIIndexYearly[randomtwo].price / STIIndexYearly[randomone].price));

var equationpart2 = ((1 / (duration)));

answer = (Math.pow(equationpart1, equationpart2) - 1)

a++;

}

console.log('break;')

});```

反對回復 2022-05-22

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如何確保選定的選項值與隨機變量方程的生成值相匹配

如何確保選定的選項值與隨機變量方程的生成值相匹配

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