我正在嘗試創建一個每個鍵具有多個值的字典。例如：top_10 = ['Volkswagen_Golf_1.4', 'BMW_316i', 'Ford_Fiesta', 'BMW_318i', 'Volkswagen_Polo', 'BMW_320i', 'Opel_Corsa', 'Renault_Twingo', 'Volkswagen_Golf', 'Opel_Corsa_1.2_16V']common_brands = ['volkswagen', 'bmw', 'opel', 'mercedes_benz', 'audi', 'ford']我想創建一個看起來像這樣的字典：{'volkswagen': ['Volkswagen_Golf_1.4', 'Volkswagen_Polo', 'Volkswagen_Golf'], 'bmw': ['BMW_316i', 'BMW_318i', 'BMW_320i'], 'opel': ['Opel_Corsa', 'Opel_Corsa_1.2_16V'],'ford': ['Ford_Fiesta'], 'Renault': ['Reanault_Twingo']}使用我嘗試過的代碼，每個品牌只能獲得一個型號，并且找不到添加不在 common_brands 列表中的品牌的方法。models_by_brand = {}for brand in common_brands: for model in top_10: if brand in model.lower(): models_by_brand[brand] = [model]models_by_brand輸出：{'bmw': ['BMW_320i'], 'ford': ['Ford_Fiesta'], 'opel': ['Opel_Corsa_1.2_16V'], 'volkswagen': ['Volkswagen_Golf']}
3 回答
慕俠2389804
TA貢獻1719條經驗 獲得超6個贊
您可以使用defaultdict并拆分車輛的名稱以獲得品牌（如果這些已標準化）：
from collections import defaultdict
models_by_brand = defaultdict(list)
for model in top_10:
brand = model.lower().split('_')[0]
models_by_brand[brand].append(model)
通過使用defaultdict，您可以編寫models_by_brand[brand].append(model)，如果brand字典中當前沒有模型，將創建并使用一個空列表。
Helenr
TA貢獻1780條經驗 獲得超4個贊
# The following code should work just fine.
top_10 = ['Volkswagen_Golf_1.4', 'BMW_316i', 'Ford_Fiesta', 'BMW_318i', 'Volkswagen_Polo', 'BMW_320i', 'Opel_Corsa',
'Renault_Twingo', 'Volkswagen_Golf', 'Opel_Corsa_1.2_16V']
common_brands = ['volkswagen', 'bmw', 'opel', 'mercedes_benz', 'audi', 'ford']
result = {}
cars = []
# For each car brand
for k in common_brands:
# For each car model
for c in top_10:
# if car brand present in car model name append it to list
if k.lower() in c.lower():
cars.append(c)
# if cars list is not empty copy it to the dictionary with key k
if len(cars) > 0:
result[k] = cars.copy()
# Reset cars list for next iteration
cars.clear()
print(result)
慕無忌1623718
TA貢獻1744條經驗 獲得超4個贊
如果要保留代碼的結構，請使用列表：
models_by_brand = {}
for brand in common_brands:
model_list=[]
for model in top_10:
if brand in model.lower():
model_list.append(model)
models_by_brand[brand] = model_list
models_by_brand = {k:v for k,v in models_by_brand.items() if v!=[]}
輸出：
{'volkswagen': ['Volkswagen_Golf_1.4', 'Volkswagen_Polo', 'Volkswagen_Golf'],
'bmw': ['BMW_316i', 'BMW_318i', 'BMW_320i'],
'opel': ['Opel_Corsa', 'Opel_Corsa_1.2_16V'],
'ford': ['Ford_Fiesta']}
不過，@Holt 的答案將是最有效的答案。
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