我有一本包含唯一 ID、姓名和生日的字典。這本字典就像一個生日數據庫，我的挑戰是我不知道如何在其中放入多個 ID。db = {"id": 1, "fn": "JM", "ln" : "Cruz", "dob": "October 5, 1980"}db1 = {"id": 2, "fn": "JD", "ln" : "Castillo", "dob": "August 18, 1979"}db2 = {"id": 3, "fn": "Maria", "ln" : "Torres", "dob": "August 3, 1992"}print("ID: " + str(db["id"]))print("Full Name: " + db["fn"] + " " + db["ln"])print("Birthday: " + db["dob"])print("----------------------")print("ID: " + str(db1["id"]))print("Full Name: " + db1["fn"] + " " + db1["ln"])print("Birthday: " + db1["dob"])print("----------------------")print("ID: " + str(db2["id"]))print("Full Name: " + db2["fn"] + " " + db2["ln"])print("Birthday: " + db2["dob"])print("----------------------")在上面的代碼中，您會注意到我必須重復創建字典才能枚舉多組 ID、姓名和生日。有沒有辦法將這些鍵轉換為變量，并給出相同的輸出？
3 回答
開滿天機
TA貢獻1786條經驗 獲得超13個贊
你可以簡單地使用一個列表來達到這個目的
dblist = []
dblist.append( {"id": 1, "fn": "JM", "ln" : "Cruz", "dob": "October 5, 1980"})
dblist.append( {"id": 2, "fn": "JD", "ln" : "Castillo", "dob": "August 18, 1979"})
dblist.append({"id": 3, "fn": "Maria", "ln" : "Torres", "dob": "August 3, 1992"})
for db in dblist:
print("ID: " + str(db["id"]))
print("Full Name: " + db["fn"] + " " + db["ln"])
print("Birthday: " + db["dob"])
print("----------------------")
輸出
ID: 1
Full Name: JM Cruz
Birthday: October 5, 1980
----------------------
ID: 2
Full Name: JD Castillo
Birthday: August 18, 1979
----------------------
ID: 3
Full Name: Maria Torres
Birthday: August 3, 1992
----------------------
jeck貓
TA貢獻1909條經驗 獲得超7個贊
您只能創建一個dict，并且密鑰是用戶 ID。其他信息如“fn, ln, dob”可能在列表中。您將按特定順序附加這 3 個信息，以便您可以從列表中檢索任何必要的信息。
樣本：
db = {"1" : [fn1, ln1, dob1], "2": [fn2, ln2, dob2]}
三國紛爭
TA貢獻1804條經驗 獲得超7個贊
db = [{"id": 1, "fn": "JM", "ln" : "Cruz", "dob": "October 5, 1980"}, {"id": 2, "fn": "JD", "ln" : "Castillo", "dob": "August 18, 1979"}, {"id": 3, "fn": "Maria", "ln" : "Torres", "dob": "August 3, 1992"}]
for i in db:
print(f"ID: {i['id']}\nFull Name: {i['fn']} {i['ln']}\nBirthday: {i['dob']}\n{'-' * 22}")
或者你可以“玩”拆包：
for i in db:
print("ID: {}\nFull Name: {} {}\nBirthday: {}\n".format(*i.values()) + "-" * 22)
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