我有自動生成的代碼。簡化版：package main// begin of Afunc main(){    ParseReader("x")}func parseInclude(fileName string) (interface{}, error) {    got, _ := ParseReader(fileName)    return got, nil}// end of Atype grammar struct {    pos   int    run  func(*parser) (interface{}, error)}var g = &grammar{    pos:  1,    run: (*parser).callonIncludeOp1,}type parser struct {    filename string    cur      current}func (p *parser) callonIncludeOp1() (interface{}, error) {    return p.cur.onIncludeOp1("x")}func (p *parser) parse(g *grammar) (val interface{}, err error) {    return g.pos, nil}type current struct {    pos  int }// Bfunc (c *current) onIncludeOp1(qfilename interface{}) (interface{}, error) {    got, _ := parseInclude("x")    return got, nil}func ParseReader(filename string) (interface{}, error) {    p := &parser{ filename: filename }    return p.parse(g)}編譯后出現錯誤./prog.go:19: initialization loop:    /home/gCDfp4/prog.go:19 g refers to    /home/gCDfp4/prog.go:25 (*parser).callonIncludeOp1 refers to    /home/gCDfp4/prog.go:36 (*current).onIncludeOp1 refers to    /home/gCDfp4/prog.go:7 parseInclude refers to    /home/gCDfp4/prog.go:41 ParseReader refers to    /home/gCDfp4/prog.go:19 g我需要在語法上進行遞歸調用，因為我有預處理器運算符“#include”來解析其他文件。因為它是自動生成的代碼，所以我只能修改塊 A 或函數 B 中的代碼。我怎樣才能打破初始化周期？