我正在嘗試實現一個使用 PasswordDigest 身份驗證的 JAX-WS Web 服務客戶端。這是我的網絡服務客戶端：import java.io.ByteArrayInputStream;import java.io.IOException;import java.util.ArrayList;import java.util.List;import javax.annotation.PostConstruct;import javax.ejb.Stateless;import javax.xml.ws.Binding;import javax.xml.ws.BindingProvider;import javax.xml.ws.WebServiceRef;import javax.xml.ws.handler.Handler;import javax.xml.ws.soap.AddressingFeature;@Statelesspublic class JaxWsService { /** * We cache the web service client, but on a thread local variable to avoid any potential multi-threading * issues. */ private ThreadLocal<MyService> threadLocalClient = new ThreadLocal<MyService>(); @WebServiceRef(wsdlLocation = "http://localhost:9999/mockMyService?WSDL") private MyServiceInterface service; @PostConstruct private void init() { AddressingFeature feature = new AddressingFeature(true, false); MyService proxy = service.getMyService(feature); List<Handler> handlerChain = new ArrayList<Handler>(); //Add a handler to the handler chain handlerChain.add( new PasswordDigestHeaderHandler() ); Binding binding = ( ( BindingProvider )proxy ).getBinding(); binding.setHandlerChain(handlerChain); threadLocalClient.set(proxy); } public Response doSomething(String guid) { MyService client = threadLocalClient.get(); return client.doSomething(guid); }}..這些是我由 ClientGenTask 生成的 Web 服務工件：@WebServiceClient...public class MyServiceInterface extends Service{...@WebService...@XmlSeeAlso({ ObjectFactory.class})public interface MyService {
2 回答
呼喚遠方
TA貢獻1856條經驗 獲得超11個贊
試試這個init()方法，你可能需要添加一個WebLogic憑證提供者：
private void init() {
AddressingFeature feature = new AddressingFeature(true, false);
MyService proxy = service.getMyService(feature);
List<Handler> handlerChain = new ArrayList<>();
// Add a handler to the handler chain
handlerChain.add(new PasswordDigestHeaderHandler());
BindingProvider bindingProvider = (BindingProvider) proxy;
Binding binding = bindingProvider.getBinding();
binding.setHandlerChain(handlerChain);
// weblogic.xml.crypto.wss.provider.CredentialProvider
// weblogic.wsee.security.unt.ClientUNTCredentialProvider
List<CredentialProvider> credProviders = new ArrayList<>();
credProviders.add(new ClientUNTCredentialProvider(USERNAME.getBytes(), PASSWORD.getBytes()));
Map<String, Object> context = bindingProvider.getRequestContext();
// weblogic.xml.crypto.wss.WSSecurityContext
context.put(WSSecurityContext.CREDENTIAL_PROVIDER_LIST, credProviders);
// weblogic.security.SSL.TrustManager
context.put(
WSSecurityContext.TRUST_MANAGER,
new TrustManager() {
public boolean certificateCallback(X509Certificate[] chain, int validateErr) {
return true;
}
}
);
threadLocalClient.set(proxy);
}
慕田峪9158850
TA貢獻1794條經驗 獲得超8個贊
試試這個。
下載描述您的服務的 WSDL 文件并通過注釋掉定義wsp:PolicyReference:的行來修改它。
將它放在一個文件夾中，該文件夾將包含在您的 jar/war/ear 文件中（例如 META-INF/wsdl）。
在您的 Web 服務客戶端中，更改您的 @WebServiceRef 注入以引用此本地/捆綁版本的 WSDL：
@WebServiceRef(wsdlLocation = "META-INF/wsdl/MyService.wsdl")
private MyServiceInterface service;
將您的客戶端初始化代碼修改為如下所示：
AddressingFeature feature = new AddressingFeature(true, false);
MyService proxy = service.getMyService(feature);
BindingProvider bindingProvider = (BindingProvider) proxy;
List<Handler> handlerChain = new ArrayList<Handler>();
//Add a handler to the handler chain
handlerChain.add( new PasswordDigestHeaderHandler() );
Binding binding = bindingProvider.getBinding();
binding.setHandlerChain(handlerChain);
// Add these two lines, to point to the remote service
Map<String, Object> context = bindingProvider.getRequestContext();
context.put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY, REMOTE_SERVICE_ENDPOINT);
threadLocalClient.set(proxy);
... 其中 REMOTE_SERVICE_ENDPOINT 是您正在訪問的遠程 Web 服務的 URL。
那應該這樣做。您不必修改 PasswordDigestHeaderHandler 實現。
我在完全相同的問題上花了相當多的時間，但這個線程讓我走上了正確的道路：https ://community.oracle.com/thread/2485783 。
祝你好運。
添加回答
舉報
0/150
提交
取消