我想要一個鍵盤記錄器，它通過按下一個鍵（任何鍵）來激活，然后將在設定的時間量（例如 10 秒）內按下的所有鍵保存在一個列表中，然后打印出來。我試過這個：from pynput import keyboardfrom time import sleepdef on_press(key): global recording, keys_pressed if not recording: recording = True sleep(10) print(" ".join(keys_pressed)) recording = Falselistener = keyboard.Listener( on_press=on_press)listener.start()def on_release(key): global recording if recording: print("key pressed") global keys_pressed Key = str(key) if Key.startswith("Key."): keys_pressed.append(Key[4:].strip("'")) else: keys_pressed.append(str(key).strip("'"))listener2 = keyboard.Listener( on_release=on_release)listener2.start()keys_pressed = []recording = Falsewhile True: pass它有點工作，但它多次打印我顯然不想要的列表。該程序運行也非常緩慢。如果您知道任何解決方案，請告訴我。
1 回答
子衿沉夜
TA貢獻1828條經驗 獲得超3個贊
它多次打印我顯然不想要的列表
每次按下按鈕時，您都明確要求它打印列表
print(" ".join(keys_pressed))
此外，我無法理解您為什么要嘗試實現 2 個偵聽器？？？
我會做更多這樣的事情，盡管我確信那里還有一個更漂亮的解決方案！
from pynput import keyboard
from time import time
my_log = []
started = False
start_time = time() # just here to initialize, won't be used until started = True
def on_press(key):
global started
global start_time
if started is False:
started = True
start_time = time()
print("starting timer")
try:
character = '{0}'.format(key.char)
except AttributeError:
character = '{0}'.format(key)
my_log.append(character)
def listen():
global started
print('keyboard listener is initialized')
with keyboard.Listener(on_press=on_press):
while True:
if started:
now = time()
if now - start_time > 10:
break
return # end our listener
listen()
print("done listening")
print(my_log)
示例輸出的樣子（有點混亂，因為打印與鍵入的內容結合在一起）：
keyboard listener is initialized
astarting timer
bcdefghijklmnopqrstuvwxyzdone listening
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
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