我有這段代碼，我想在找不到資源的情況下拋出異常Menu menu = menuService.findById(addMenuAmount.getMenuId())
.orElseThrow(com.tdk.web.exception.ResourceNotFoundException(“menu " +
addMenuAmount.getMenuId() + " not found "));但我得到一個編譯錯誤：com.tdk.web.exception cannot be resolved to a type
1 回答
肥皂起泡泡
TA貢獻1829條經驗 獲得超6個贊
試試這個并確保它com.tdk.web.exception.ResourceNotFoundException是可訪問的
Menu menu = menuService.findById(addMenuAmount.getMenuId())
.orElseThrow(() -> new com.tdk.web.exception.ResourceNotFoundException("menu " +
addMenuAmount.getMenuId() + " not found "));注意 lambda() ->和引號"menu "。
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