這是我的代碼：type Square struct { num int //Holds the number. 0 is empty}func somefunc() { squares := [4][4]Square但我得到這個錯誤：type [4][4]Square is not an expression
2 回答
夢里花落0921
TA貢獻1772條經驗 獲得超6個贊
二維數組和初始化：
package main
import (
"fmt"
)
type Square struct {
num int //Holds the number. 0 is empty
}
func main() {
squares0 := [4][4]Square{} // init to zeros
fmt.Println(squares0)
var squares [4][4]Square // init to zeros
fmt.Println(squares)
squares2 := [4][4]Square{{}, {}, {}, {}} // init to zeros
fmt.Println(squares2)
squares3 := [4][4]Square{
{{1}, {2}, {3}, {4}},
{{5}, {6}, {7}, {8}},
{{9}, {10}, {11}, {12}},
{{13}, {14}, {15}, {16}}}
fmt.Println(squares3)
for i := 0; i < 4; i++ {
for j := 0; j < 4; j++ {
squares[i][j].num = (i+1)*10 + j + 1
}
}
fmt.Println(squares)
}
輸出：
[[{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}]]
[[{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}]]
[[{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}]]
[[{1} {2} {3} {4}] [{5} {6} {7} {8}] [{9} {10} {11} {12}] [{13} {14} {15} {16}]]
[[{11} {12} {13} {14}] [{21} {22} {23} {24}] [{31} {32} {33} {34}] [{41} {42} {43} {44}]]
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