我有一個帶有內部列表和字典的字典列表，我需要將它們連接到一個大字典中。名單是這樣的：[{'total': {'last_day': '7'}}, {'total': {'progress': '07/04'}}, {'total': {'piecies': '3008'}}, {'total': {'week': ['16.0']}}, {'total': {'week': ['17.0']}}, {'total': {'week': ['15.0']}}, {'total': {'week': ['17.0']}}, {'total': {'week': ['16.0']}}, {'total': {'week': ['13.0']}}, {'total': {'week': ['6.0']}}, {'tkts': [{'tktvalue': '13.5'}]}, {'tkts': [{'month': {'consuntivato_pezzi': '2346'}}]}, {'tkts': [{'month': {'consuntivato_euro': '31671.00'}}]}, {'tkts': [{'month': {'preventivato_pezzi': '9897'}}]}]我嘗試了一些 for 循環和遞歸函數，但沒有很好的結果for vars in temporary_var: for title in vars: try: try: table_var[title].update(vars[title]) except KeyError: table_var[title] = vars[title] except AttributeError: table_var[title].append(vars[title][0])但我只能得到這個：{'total': {'last_day': '7', 'progress': '07/04', 'volumes': '3008', 'week': ['6.0']}, 'tkts': [{'service': 'SOSPC'}, {'tktvalue': '13.5'}, {'month': {'volumes1': '2346'}}, {'month': {'volumes2': '31671.00'}}, {'month': {'volumes3': '9897'}}]}但我需要這個：{'total': {'last_day': '7', 'progress': '07/04', 'volumes': '3008', 'week': ['16.0', '17.0', '15.0', '17.0', '16.0', '13.0','6.0']}, 'tkts': [{'service': 'SOSPC', 'tktvalue': '13.5', 'month': {'volumes1': '2346', 'volumes2': '31671.00', 'volumes3': '9897'}}]}
2 回答
慕尼黑8549860
TA貢獻1818條經驗 獲得超11個贊
試試這個，它會得到你想要的輸出：
lst=[{'total': {'last_day': '7'}},
{'total': {'progress': '07/04'}},
{'total': {'piecies': '3008'}},
{'total': {'week': ['16.0']}},
{'total': {'week': ['17.0']}},
{'total': {'week': ['15.0']}},
{'total': {'week': ['17.0']}},
{'total': {'week': ['16.0']}},
{'total': {'week': ['13.0']}},
{'total': {'week': ['6.0']}},
{'tkts': [{'tktvalue': '13.5'}]},
{'tkts': [{'month': {'consuntivato_pezzi': '2346'}}]},
{'tkts': [{'month': {'consuntivato_euro': '31671.00'}}]},
{'tkts': [{'month': {'preventivato_pezzi': '9897'}}]}
]
d={} # the dictionary that will hold the result
for dd in lst: # for each dictionary in the list of dictionaries
for key,value in dd.items():
if key not in d: # key does not exist in dictionary d
d[key]=value
else: # key exists in dictionary d
if isinstance(value,dict): # check if the value is a dictionary or a list
for key1,value2 in value.items():
if key1 not in d[key]:
d[key]={**d[key],**value} # combine the dictionaries
else:
d[key][key1].append(value2[0])
elif isinstance(value,list): # check if the value is a list
if isinstance(value[0],dict): # check if the value is a dictionary or a list
for key1,value2 in value[0].items():
if key1 not in d[key][0]:
d[key][0]={**d[key][0],**value[0]}
else:
d[key][0][key1]={**d[key][0][key1],**value2}
print(d)
輸出：{'total': {'last_day': '7', 'progress': '07 / 04 ',' piecies ':' 3008 ',' week ': ['16 .0', '17 .0' , '15 .0', '17 .0', '16 .0', '13 .0',' 6.0 ']},' tkts ': [{' tktvalue ': '13 .5', '月' ：{'consuntivato_pizzi'：'2346'，'final_euro'：'31671.00'，'quoted_pieces'：'9897'}}]}
縹緲止盈
TA貢獻2041條經驗 獲得超4個贊
嘗試在此處使用默認列表。您可以了解有關它們的更多信息collections.defaultdict
from collections import defaultdict
result = defaultdict(list)
for sequence in (yourdict):
for keys,dictionary in sequence.items():
result[keys].append(dictionary)
print(dict(result))
輸出 ：
{'total': [{'last_day': '7'}, {'progress': '07/04'}, {'piecies': '3008'}, {'week': ['16.0']}, {'week': ['17.0']}, {'week': ['15.0']}, {'week': ['17.0']}, {'week': ['16.0']}, {'week': ['13.0']}, {'week': ['6.0']}], 'tkts': [[{'tktvalue': '13.5'}], [{'month': {'consuntivato_pezzi': '2346'}}], [{'month': {'consuntivato_euro': '31671.00'}}], [{'month': {'preventivato_pezzi': '9897'}}]]}
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