我的 PHP、js 代碼有點問題。當我提交表單頁面正在重新加載但輸入復選框未處于選中模式時，但我需要的是。我想也許我需要從 URL 獲取參數，然后將它與 DOM 元素進行比較，然后為輸入設置檢查模式？PHP代碼：if(isset($_GET['user_id'])) {    try {        $PDO_connection = new PDO($dsn, $user, $password, $opt);        $queryForUserInfo = "SELECT position, dateOfBirth, rank, tellNumber, worker_id                                               FROM workers                                               WHERE user_id = :id";        $sth = $PDO_connection->prepare($queryForUserInfo);        $sth->bindParam(":id", $_GET['user_id'], PDO::PARAM_STR);        $sth->execute();        $result = $sth->fetchAll(PDO::FETCH_ASSOC);        $queryForComeAndReturnUserInfo = "SELECT date_come, date_return                                      FROM outside_records                                       WHERE worker_id = {$result[0]['worker_id']}                                      ORDER BY date_return DESC";        $sth1 = $PDO_connection->prepare($queryForComeAndReturnUserInfo);        $sth1->bindParam(":id", $_GET['user_id'], PDO::PARAM_STR);        $sth1->execute();        $outsideSchedule = $sth1->fetchAll(PDO::FETCH_ASSOC);    } catch (PDOException $e){        echo $e->getMessage();    };}<form action="<?php echo $_SERVER['PHP_SELF']?>" method="get" id="listOfUsers_form">    <!--just for getting id to make db query-->    <?php foreach ($AllUsers as $user):?>        <tr class='usersList'>            <td><input type='checkbox' name='user_id' value='<?php if(isset($user)){echo $user['user_id'];}?>'></td>            <td><?php echo $user['name'];?></td>            <td><?php echo $user['surname'];?></td>            <td><?php echo $user['position'];?></td>        </tr>    <?php endforeach; ?></tbody></form>