2 回答

TA貢獻1842條經驗 獲得超13個贊
由于您的最終結果for的語句在循環內部,因此內部的語句for只會運行一次并且不會給出正確的答案。
因此,您必須按如下方式更改代碼。
public static int[] eliminateDuplicates(int[] arr)
{
int[] temp = new int[arr.length];
int size = 0;
for (int i = 0; i < arr.length; i++) {
if (linearSearch(temp, arr[i]) == -1) {
temp[size] = arr[i];
size++;
}
}
int[] result = new int[size];
for (int i = 0; i < size; i++) {
result[i] = temp[i];
}
return result;
}

TA貢獻1827條經驗 獲得超8個贊
整數數組中的默認值為 0,Random.nextInt() 可以生成 0 個隨機值,當您運行線性搜索時,0 將不會包含在最終結果數組中。我已經修改了 Random.nextInt() 以便它不會生成 0 個隨機數:
import java.util.Random;
import java.util.Scanner;
public class HelloCodiva
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
Random generator = new Random();
System.out.println("Enter array length: ");
int[] a = new int[input.nextInt()];
for (int i = 0; i<a.length; i++){
a[i] = generator.nextInt(a.length*2)+1;//So that 0 is not generated
}
int[] result = eliminateDuplicates(a);
for (int originalValue: a){
System.out.println(originalValue+ " ");
}
System.out.println("The new numbers are: " + result.length);
System.out.println("The double numbers were:");
for (int b : result){
System.out.println(b + " ");
}
}
public static int[] eliminateDuplicates(int[] arr)
{
int[] temp = new int[arr.length];
int size = 0;
for (int i = 0; i < arr.length; i++) {
if (linearSearch(temp, arr[i]) == -1) {
temp[size] = arr[i];
size++;
}
}
int[] result = new int[size];
System.arraycopy(temp, 0, result, 0, size);
return result;
}
public static int linearSearch(int[] arr, int key)
{
for(int i = 0; i<arr.length; i++)
{
if (key == arr[i])
return i;
}
return -1;
}
}
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