我一直試圖弄清楚它有一段時間了，而不是最擅長編程。這是我到目前為止所擁有的。字典的鍵應該是列表中員工的頭銜，值是具有該特定頭銜的員工數。employees = [ { "email": "[email protected]", "employee_id": 101, "firstname": "Jonathan", "lastname": "Calderon", "title": "Mr", "work_phone": "(02) 3691 5845" }, { "email": "[email protected]", "employee_id": 102, "firstname": "Christopher", "lastname": "Hansen", "title": "Mr", "work_phone": "(02) 5807 8580" }, { "email": "[email protected]", "employee_id": 103, "firstname": "Isabella", "lastname": "Dorsey", "title": "Mrs", "work_phone": "(02) 6375 1060" }, { "email": "[email protected]", "employee_id": 104, "firstname": "Barbara", "lastname": "Baker", "title": "Ms", "work_phone": "(03) 5729 4873" }]#my workfor i in employees: print(i['title'])employees.count('title')print()#my output:MrMrMrsMs#expected output:{'Ms': 1, 'Mrs': 1, 'Mr': 2}
3 回答
胡子哥哥
TA貢獻1825條經驗 獲得超6個贊
collections.Counter
from collections import Counter
counts = Counter([x['title'] for x in employees])
print(counts)
# Counter({'Mr': 2, 'Mrs': 1, 'Ms': 1})
如果有任何沒有title字段的記錄，請使用：
counts = Counter([x.get("title", None) for x in employees])
# Counter({'Mr': 2, 'Mrs': 1, 'Ms': 1, None: 1})
在這里，如果不存在，.get將獲取title或返回的值。Nonetitle
呼啦一陣風
TA貢獻1802條經驗 獲得超6個贊
使用 collections.defaultdict
前任：
from collections import defaultdict
result = defaultdict(int)
for i in employees:
result[i["title"]] += 1
print(result)
輸出：
defaultdict(<type 'int'>, {'Mrs': 1, 'Ms': 1, 'Mr': 2})
米琪卡哇伊
TA貢獻1998條經驗 獲得超6個贊
你可以用一個計數器來做到這一點：
from collection import Counter
titles = [e['title'] for e in employees]
counts = Counter(titles)
# Counter({'Mr': 2, 'Mrs': 1, 'Ms': 1})
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