盡管 random.shuffle 每次都會使賠率隨機化，但代碼始終顯示玩家 1 為贏家。在如何洗牌或玩家 1 如何總是贏得比賽方面，我沒有任何直接的模式，因為他們并不總是每輪都贏。不管怎樣，他們總是贏得整場比賽。我想知道這是否是我使用 sudo-random shuffling 的問題，或者我是否在某個時候犯了一個我沒有注意到的邏輯錯誤。我曾嘗試在不同的點放置打印件，以嘗試查看我是否在不同的點得到了無法預料/不希望的結果，但沒有注意到任何奇怪的輸出。我嘗試對值進行雙重洗牌，看看是否有任何改變，但結果仍然總是玩家 1。當我不洗牌時，玩家 2 確實贏了，所以我假設所有的數學和檢查都是正確的。cards = ['r1','r2','r3','r4','r5','r6','r7','r8','r9','r10','b1','b2','b3','b4','b5','b6','b7','b8','b9','b10','y1','y2','y3','y4','y5','y6','y7','y8','y9','y10']#cardShufflerdef cardShuffler(cards): from random import shuffle shuffle(cards) print(cards) return(cards)#cardArrayDeciphers#colourdef cardColour(selectedCard): colour = selectedCard[0] #takes the letter on the card intidacting colour return colour#numberdef cardNum(selectedCard): number = int(selectedCard[1]) #takes number in a card and convert str to int return number#winnerCalcdef winnerCalc(p1Card, p2Card): colour1 = cardColour(p1Card) colour2 = cardColour(p2Card) num1 = cardNum(p1Card) num2 = cardNum(p2Card) #pattern should go red > black > yellow > red if(colour1 == "r")and(colour2 == "b"): winner = ("p1") elif(colour1 == "b")and(colour2 == "y"): winner = ("p1") elif(colour1 == "y")and(colour2 == "r"): winner = ("p1") elif num1 > num2: winner = ("p1") else: winner = ("p2") print("winner "+str(winner)) #debug return winner#gameValssearchVal = -1p1WinCards = []p2WinCards = []cards = cardShuffler(cards) #function = cardShuffle#gameLoop [player 1 always wins!]while (searchVal != 29): p1Given = searchVal + 1 #where the code looks for p1 card p2Given = searchVal + 2 p1Card = cards[p1Given] p2Card = cards[p2Given] searchVal = p2Given winner = winnerCalc(p1Card, p2Card) #function = winnerCalc if winner == "p1": #giving the winner all the cards p1WinCards.append(p1Card) p1WinCards.append(p2Card)我希望winnerAbsolute 的輸出是sudo_random，但結果總是玩家1。
2 回答
達令說
TA貢獻1821條經驗 獲得超6個贊
您的 if 語句非常有利于 p1 獲勝。我希望 'p2' 獲勝的示例代碼，因為 p2 具有優越的顏色：
colour1 = 'b'
colour2 = 'r'
num1 = 2
num2 = 1
if(colour1 == "r")and(colour2 == "b"):
print("p1")
elif(colour1 == "b")and(colour2 == "y"):
print("p1")
elif(colour1 == "y")and(colour2 == "r"):
print("p1")
elif num1 > num2:
print("p1")
else:
print("p2")
>>> p1
玩家 1 在這里獲勝，因為沒有檢查玩家 2 是否具有更好的顏色。要正確檢查正確的獲勝者，您可以將 if 語句修改為以下邏輯：
colour1 = 'b'
colour2 = 'r'
num1 = 2
num2 = 1
if (colour1 == "r" and colour2 == "b") or (colour1 == "b" and colour2 == "y") or (colour1 == "y" and colour2 == "r"):
print("p1")
elif (colour2 == "r" and colour1 == "b") or (colour2 == "b" and colour1 == "y") or (colour2 == "y" and colour1 == "r"):
print("p2")
elif num1 > num2:
print("p1")
else:
print("p2")
>>> p2
您可以在其中將最后一個 elif 和 else 重構為以下代碼行：
colour1 = 'b'
colour2 = 'r'
num1 = 2
num2 = 1
if (colour1 == "r" and colour2 == "b") or (colour1 == "b" and colour2 == "y") or (colour1 == "y" and colour2 == "r"):
print("p1")
elif (colour2 == "r" and colour1 == "b") or (colour2 == "b" and colour1 == "y") or (colour2 == "y" and colour1 == "r"):
print("p2")
else:
print("p1" if num1 > num2 else "p2")
>>> p2
慕工程0101907
TA貢獻1887條經驗 獲得超5個贊
首先，玩你的游戲很有趣。其次，正如我所懷疑的，錯誤總是出在多個 if 語句中，這特別棘手，因為您認為自己是徹底的，并且在 ned 中它會咬你！
為了清楚起見，讓我們舉個例子：
p1Card = y8 ,p2Card = b1
讓我們運行它：
if(colour1 == "r")and(colour2 == "b") # False
winner = ("p1")
elif(colour1 == "b")and(colour2 == "y")# False
winner = ("p1")
elif(colour1 == "y")and(colour2 == "r")# False
winner = ("p1")
elif num1 > num2: # True
winner = ("p1")
else:
winner = ("p2")
因此，贏家 P1 而它應該是 P2。有多種方法可以避免這種情況，但這應該留給您自己解決:)
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