我的文本文件看起來像這樣..每行由一個空格分隔。dream 4.345 0.456 6.3456play 0.1223 -0.345 5.3543faster 1.324 2.435 -2.2345我想寫字典并將其打印如下...dream: [4.345 0.456 6.3456]play: [0.1223 -0.345 5.3543]faster: [1.324 2.435 -2.2345]我的代碼如下。請糾正我這個...with open("text.txt", "r") as file: for lines in file: line = lines.split() keys = b[0] values = b[1:] d[keys] = valuesprint d
3 回答
青春有我
TA貢獻1784條經驗 獲得超8個贊
對于 python3，如果你想得到想要的結果：
d = {}
with open("text.txt", "r") as file:
for lines in file:
line = lines.split()
keys = line[0]
values = list(map(float, line[1:]))
d[keys] = values
for k in d :
print(k , d[k])
元芳怎么了
TA貢獻1798條經驗 獲得超7個贊
你可以這樣試試。
輸入.txt
dream 4.345 0.456 6.3456
play 0.1223 -0.345 5.3543
faster 1.324 2.435 -2.2345
編寫器.py
output_text = '' # Text
d = {} # Dictionary
with open("input.txt") as f:
lines = f.readlines()
for line in lines:
line = line.strip()
arr = line.split()
name = arr[0]
arr = arr[1:]
d[name] = arr
output_text += name + ": [" + ' '.join(arr) + "]\n"
output_text = output_text.strip() # To remove extra new line appended at the end of last line
print(d)
# {'play': ['0.1223', '-0.345', '5.3543'], 'dream': ['4.345', '0.456', '6.3456'], 'faster': ['1.324', '2.435', '-2.2345']}
print(output_text)
# dream: [4.345 0.456 6.3456]
# play: [0.1223 -0.345 5.3543]
# faster: [1.324 2.435 -2.2345]
with open("output.txt", "w") as f:
f.write(output_text)
輸出.txt
dream: [4.345 0.456 6.3456]
play: [0.1223 -0.345 5.3543]
faster: [1.324 2.435 -2.2345]
蕭十郎
TA貢獻1815條經驗 獲得超13個贊
這很簡單。請參閱下面的代碼。
dictionary = {}
with open("text.txt", "r") as file:
for lines in file:
line = lines.split()
dictionary[line[0]] = line[1:]
print(dictionary)
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