我想從我從 while 循環中獲取的數據庫數據生成完全相同的數組，該數組將傳遞給其他一些函數，并且它不接受其他任何內容。當我手動傳遞此數據時，它可以工作，因此它應該完全相同。$putArray7 =array( // "title" => "Test Product " , // "body_html" => "test description" , "images" => array ( array( "id" => "6800163209265", "attachment" => "$attachment_base64", ), array( "id" => "6800163438641", "attachment" => "$attachment_base64", ), array( "id" => "6800164880433", "attachment" => "$attachment_base64", ), ) );我試過的： $response99 = array(); $response_final = array();// data from mysql starts here while($row = mysqli_fetch_assoc($res)) { $response99[] = ['id'=>$id_img_id .',', 'attachment'=>$attachment_base64]; }現在嘗試在此處重新創建整個數組：// did not work $response_final[] = ['title'=>"Test Product 53","body_html" => "test description" , 'images'=>$response99];試過這個： $response_final[] = ['title'=>"Test Product 53","body_html" => "test description" , 'images'=>[$response99]];這個也不起作用：嘗試了其他幾種方法。任何幫助都會很棒。想要生成完全一樣的$putArray7.
1 回答
慕哥6287543
TA貢獻1831條經驗 獲得超10個贊
像這樣做：
$response99 = array();
$response_final = array();
while($row = mysqli_fetch_assoc($res)){
$a = array();
$a['id'] = $row['id'];
$a['attachment'] = $row['attachment'];
$response99[] = $a;
}
$response_final = array(
'title' => "Test Product 53",
'body_html' => "test description" ,
'images' => $response99
);
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