到目前為止，我只能在每個 if 語句之后硬編碼相同的代碼段，只需要更改 getAdjacentCells(id) 的參數即可。我一直無法找到重復這部分的方法。我認為這可以遞歸完成，但我不知道該怎么做。編輯：我最初輸入 isCellEmpty 得到了一個對象數組：[{topLeft: null}, {topCenter: "cell-1-2"}, {topRight: "cell-1-3"}, {middleLeft: null}, {middleRight: "cell-2-3"}]，當實際上是單個對象時：{topLeft: null, topCenter: "cell-1-2", topRight: "cell-1-3", middleLeft: null , middleRight: "cell-2-3"}// Gets an object that looks like this: {topLeft: null, topCenter: "cell-1-2", topRight: "cell-1-3", middleLeft: null, middleRight: "cell-2-3"}function isCellEmpty(adjacentCells) {  Object.values(adjacentCells).forEach(id => {    // Checks that the ids in stored in the object values do not equal null    if (id !== null) {      board[getBoardPosition(id)].opened = true;      // getAdjacentCells() will return either an array of objects similar to the one the function takes as an argument or an integer      // if getAdjacentCells(id) returns a number, add a div to the HTML element with that id      if (typeof (getAdjacentCells(id)) === "number") {        // Removes all other divs, this prevents repetition        $("#" + id).empty();        // Appends an empty div        $("#" + id).append("<div></div>");      // HERE'S WHERE IT STARTS: If getAdjacentCells(id) returns an object, do the same as above with every id in it      } else if (typeof (getAdjacentCells(id)) === "object") {        Object.values(getAdjacentCells(id)).forEach(id2 => {          if (id2 !== null) {            board[getBoardPosition(id2)].opened = true;            if (typeof (getAdjacentCells(id2)) === "number") {              $("#" + id2).empty();              $("#" + id2).append("<div></div>");            // HERE IT REPEATS:             } else if (typeof (getAdjacentCells(id2)) === "object") {              ...             }          }        })      }    }  });}