題目：應用VC++6.0的編輯環境構造一個類Jhtx及其派生類，該類主要實現關于幾何圖形的基本操作。對于基類“幾何圖形”，有求面積、求體積的函數（純虛函數），其派生類圓和矩形主要有初始化（構造函數），求面積，求周長操作，類圓的派生類圓球和圓柱有求表面積、體積操作。 試在主函數中分別定義圓、圓球、圓柱以及矩形的對象，并調用其成員函數實現其相應操作。以下是我的程序，但是有一些錯誤，都是相同的錯誤，請大家指教。#include<iostream.h>class Geometry{public:Geometry(double a,double b,double c){x=a,y=b,c=z;}~Geometry(){};virtual double GetArea()=0;double GetPerimeter();virtual double GetColume()=0;virtual void Show()=0;protected:double x,y,z;};class Circle:public Geometry{protected:double r;public:Circle(double a):Geometry(a,0,0){r=a;}~Circle(){};double GetArea(){return 3.14*r*r;} double GetPerimeter(){return 6.28*r;}virtual double GetColume(){return 0;}void Show(){cout<<"Area is:"<<GetArea()<<endl;cout<<"Perimeter is:"<<GetPerimeter()<<endl;} };class Rectangle:public Geometry{public: Rectangle(double a,double b):Geometry(a,b,0){}~Rectangle(){};double GetArea(){return x*y;}double GetPerimeter(){return x+y;} virtual double Getolume(){return 0;}void Show(){cout<<"Area is:"<<GetArea()<<endl;cout<<"Perimeter is:"<<GetPerimeter()<<endl;}};class Ball:public Circle{public: Ball(double a):Circle(a){};~Ball(){};double GetArea(){return 4*3.14*x*x;}double GetColume(){return (4/3)*3.14*x*x*x;}double GetPerimeter(){return 0;}void Show(){cout<<"Area is:"<<GetArea()<<endl;cout<<"Getcolume is:"<<GetColume()<<endl;}};class Column:public Circle{protected:double h;Column(double a,double h):Circle(a),h(h){}~Column(){};double GetArea(){return 2*3.14*x*x+2*3.14*x*h;}double GetColume(){return 3.14*x*x*h;}double GetPerimeter(){return 0;} void Show(){cout<<"Area is:"<<GetArea()<<endl;cout<<"Getcolume is:"<<GetColume()<<endl;}};int main(){ Geometry *p;Circle ob1(1);Rectangle ob2(2,2);Ball ob3(3);Column ob4(4,3);p=&ob1;p->GetArea();p->GetPerimeter();p->Show();p=&ob2;p->GetArea();p->GetPerimeter();p->Show();p=&ob3;p->GetArea();p->GetPerimeter();p->Show();p=&ob4;p->GetArea();p->GetPerimeter();p->Show();return 0;}
以下內容是關于C++面向對象程序設計問題，求解釋~
寶慕林4294392
2021-11-20 15:11:17
