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返回不重復的數組值

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返回不重復的數組值

JavaScript

慕碼人8056858 2021-11-18 20:55:26

var arr = [ {name:"Grace", age: "28"}, {name:"Peter", age: "15"}, {name:"Grace", age: "28"}, {name:"John", age: "16"}, {name:"Prince", age: "19"}, {name:"John", age: "16"} ]; 我現在只想返回那些獨特的如下var new = [ {name:"Peter", age: "15"}, {name:"Prince", age: "19"},];

查看完整描述

1 回答

ABOUTYOU

TA貢獻1812條經驗獲得超5個贊

您可以使用Map和reduce

首先創建一個mapper基于name并計算每個名稱的重復次數

只選擇重復正好的值 1

const arr = [{name:"Grace", age: "28"},{name:"Peter", age: "15"},{name:"Grace", age: "28"},{name:"John", age: "16"},{name:"Prince", age: "19"},{name:"John", age: "16"}];

let mapper = arr.reduce( (op,inp) => {

let {name:key} = inp

op.set(key, op.get(key) || {value: inp, count:0})

op.get(key).count++

return op

},new Map())

let final = [...mapper.values()].reduce((op,{value,count}) => {

if(count === 1){

op.push(value)

}

return op

},[])

console.log(final)

反對回復 2021-11-18

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返回不重復的數組值

返回不重復的數組值

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