我在單擊按鈕時通過 JavaScript 發送 ajax 請求。當按鈕被點擊時，會從執行 ajax 請求的地方調用一個函數。這是調用函數的html代碼：echo "<form > ";if ($status == 'regular') {    echo "<input type='hidden' value='".$id."' name='id'>";     echo "<input type='hidden' value='official' name='status'>";    echo "<td><button class='btn btn-info' onclick='UpdateStatus(".$id.",'official')'>UPDATE TO OFFICIAL</button><br><br>";}if ($status == 'official') {     echo "<input type='hidden' value='".$id."' name='id'>";     echo "<input type='hidden' value='regular' name='status'>";echo "<td><button class='btn btn-success' onclick='UpdateStatus(".$id.",'regular')'>UPDATE TO REGULAR</button><br><br>";    }echo "</form>";UpdateStatus()是有ajax請求的函數。我從這里發送$id用戶 ID 和要更新的狀態。這是 UpdateStatus() 函數：<script>function UpdateStatus(str,str1) {if (str.length == 0) {    document.getElementById("txtHint").innerHTML = "";    return;} else {    var xmlhttp = new XMLHttpRequest();    xmlhttp.onreadystatechange = function() {      //ready    };    xmlhttp.open("GET", "update_status.php?id=" + str + "&status=" + str1, true);    xmlhttp.send();}}</script>的str和str1分別是編號和狀態。這是update_status.php：<?php$id = $_REQUEST["id"];$status = $_REQUEST["status"];$server_name = "localhost";$user_name = "root";$password = "";$db = "diwan";$conect = new mysqli($server_name, $user_name, $password, $db);if($conect->connect_error){ die("Connection failed ".$conect->connect_error); }$sql = "UPDATE user SET status = '$status' WHERE UserID = $id";if(!$conect->query($sql))      {echo "error in adding record ".$conect->error;}$result = $conect->query($sql);?>當我點擊按鈕時，我得到了這種格式的網址：http://localhost/diwan_web/manageusers.php?id=2&status=official但它不會更新數據庫中的數據。請指導我哪里錯了或者有什么遺漏。任何建議將不勝感激。