通過附加的代碼，我根據用戶名在 youtube 上進行了搜索，并顯示了結果。如果我搜索兩次，結果就會相加。我想刪除以前的結果。我嘗試使用 htmlString = card; 但它只顯示一個結果。感謝所有想幫助我解決這個問題的人。var musicCards = [];jQuery(document).ready(function() {      jQuery("#searchButton").on("click", function() {                 var query = jQuery("#queryInput").val();             if (query != "") {           loadYoutubeService(query);                       console.log(query + "");        }    });});function loadYoutubeService(query) {    gapi.client.load('youtube', 'v3', function() {        gapi.client.setApiKey('ADADADADADA');        search(query);    });}function search(query) {       var request = gapi.client.youtube.search.list({        part: 'snippet',        q: query,         type: 'channel',        maxResults: 15    });    request.execute(function(response) {               jQuery.each(response.items, function(i, item) {               if (!item['']) {                var musicCard = {};                musicCard._id = item['snippet']['customUrl'];                musicCard.title = item['snippet']['title'];              musicCard.linkprofilo = item['snippet']['channelId'];                musicCard.url = "https://www.youtube.com/channel/";                musicCard.description = item['snippet']['description'];                musicCard.immagine = item['snippet']['thumbnails']['high']['url'];                musicCards.push(musicCard);            }                                 });         renderView();    });}function renderView() {    var htmlString = "";    musicCards.forEach(function(musicCard, i) {        var card = createCard(musicCard._id, musicCard.title, musicCard.description, musicCard.url,musicCard.immagine, musicCard.linkprofilo);        htmlString += card;    });      jQuery('#youtube-utente').html(htmlString);}}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.0/jquery.min.js"></script>