我正在嘗試將來自學生姓名和分數問題的用戶輸入轉換為數組。我還需要幫助來打印數組。while 循環使用 boolean loopNaming 作為其條件，并且每次循環發生時都會更新 i 。 public static void main(String [] args) { Scanner keyboard = new Scanner(System.in); double score; boolean loopNaming=true; int i=0; String[] name = new String[i]; while(loopNaming==true) { System.out.printf("Enter name of student or done to finish: "); name[i] = keyboard.next(); if(name[i].equals("done")) { loopNaming = false; } else { System.out.println("Enter score: "); score = keyboard.nextDouble(); } i=i+1; } System.out.println(name[i]); } }
3 回答
飲歌長嘯
TA貢獻1951條經驗 獲得超3個贊
您可以簡化程序的邏輯并編寫如下內容，
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
List<String> nameList = new ArrayList<String>();
List<Double> scoreList = new ArrayList<Double>();
while (true) {
System.out.printf("Enter first name of student or done to finish: ");
String fname = keyboard.next();
if (fname.equals("done")) {
break;
}
System.out.printf("Enter last name of student: ");
String lname = keyboard.next();
nameList.add(fname + " " + lname);
System.out.println("Enter score: ");
scoreList.add(keyboard.nextDouble());
}
keyboard.close();
System.out.println("Names: " + nameList);
System.out.println("scores: " + scoreList);
}
繁華開滿天機
TA貢獻1816條經驗 獲得超4個贊
public static void main(String [] args)
{
Scanner keyboard = new Scanner(System.in);
double score;
boolean loopNaming=true;
int i=0;
ArrayList<String> name = new ArrayList<>();
while(loopNaming==true)
{
System.out.printf("Enter name of student or done to finish: ");
String input = keyboard.next();
if(input.equals("done"))
{
loopNaming = false;
}
else
{ name.add(input);
System.out.println("Enter score: ");
score = keyboard.nextDouble();
}
i=i+1; //no need to use
}
System.out.println(name);
}
您應該使用 adynamic list因為您不能在 Java 中調整數組的大小。第二點當用戶給出“完成”時，你不應該把它放在列表中，所以在插入之前檢查它。
慕妹3242003
TA貢獻1824條經驗 獲得超6個贊
您聲明了大小為 0 的 String 數組。這就是您不能向其中添加元素的原因。
import java.util.Scanner;
public class NameArray {
public static void main(String [] args){
Scanner keyboard = new Scanner(System.in);
double score[] = new double[10];
boolean loopNaming=true;
int i=0;
String namae;
String[] name = new String[10];
int count = 0;
while(loopNaming==true){
System.out.printf("Enter name of student or done to finish: ");
name[i] = keyboard.next();
if(name[i].equals("done")){
loopNaming = false;
}
else{
System.out.println("Enter score: ");
score[i] = keyboard.nextDouble();
count++;
}
i=i+1;
}
for(int j = 0; j < count; j++) {
System.out.println(name[j]+" "+score[j]);
}
}
}
試試這個代碼，或者你可以選擇任何其他數據結構。
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