我有一系列的日子需要確定周末是否在這個范圍內。如果是這樣，我將在最終范圍內添加 2 天（周一至周日，將其更改為周一至周三。（基于用戶選擇的天數，例如 5）我已經找到了一種解析日子的方法（不確定這是否是最佳實踐）并且不確定如何繼續。迄今為止：////TODO Refactor to new classDateTime startingDate = DateTime.Parse("07/25/2018");//TODO Insert variable from poted form DateTime endingDate = DateTime.Parse("07/08/2018");//TODO Insert variable from posted form var days= Enumerable.Range(0, 1 + endingDate.Subtract(startingDate).Days) .Select(offset => startingDate.AddDays(offset)) .ToList();在我看來，我需要像下面的偽代碼那樣做：if day.contains dayOfWeek.Saturday ||Or dayofWeek.Friday {Add.Days(2)}但我不知道如何。
3 回答
一只甜甜圈
TA貢獻1836條經驗 獲得超5個贊
第一個你計算所有的周末天數。然后，將結果添加到開始日期中。這是我的解決方案。希望能幫到你，朋友！
static IEnumerable<DateTime> GetDaysBetween(DateTime start, DateTime end)
{
for (DateTime i = start; i < end; i = i.AddDays(1))
{
yield return i;
}
}
DateTime startingDate = DateTime.Parse("07/25/2018");//TODO Insert variable from poted form
var numOfWeekends = GetDaysBetween(startingDate, startingDate.AddDays(7))
.Where(d => d.DayOfWeek == DayOfWeek.Saturday || d.DayOfWeek == DayOfWeek.Sunday).Count();
startingDate = startingDate.AddDays(numOfWeekends);
Console.WriteLine(startingDate);
慕少森
TA貢獻2019條經驗 獲得超9個贊
我并沒有真正理解附加部分，但是此代碼將為您提供一個沒有任何星期日或星期六的列表：
DateTime startingDate = DateTime.Parse("07/25/2018");//TODO Insert variable from poted form
DateTime endingDate = DateTime.Parse("07/08/2018");//TODO Insert variable from posted form
List<DateTime> dates = new List<DateTime>();
for (DateTime dt = startingDate; dt <= endingDate; dt = dt.AddDays(1))
if (dt.DayOfWeek != DayOfWeek.Saturday && dt.DayOfWeek != DayOfWeek.Sunday)
dates.Add(dt);
如果需要，您還可以添加計數器：
DateTime startingDate = DateTime.Parse("07/25/2018");//TODO Insert variable from poted form
DateTime endingDate = DateTime.Parse("07/08/2018");//TODO Insert variable from posted form
List<DateTime> dates = new List<DateTime>();
int couter = 0;
for (DateTime dt = startingDate; dt <= endingDate; dt = dt.AddDays(1))
{
if (dt.DayOfWeek != DayOfWeek.Saturday && dt.DayOfWeek != DayOfWeek.Sunday)
dates.Add(dt);
else
counter++;
}
或者別的什么...
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