我在 JSON 格式中得到了很大的響應，我只需要 2 個字符串，這是我的 JSON 文件，我在其中減少了更好的閱讀{ "cdn_url": "https://f.vimeocdn.com", "vimeo_api_url": "api.vimeo.com", "request": { "files": { "progressive": [ { "profile": 164, "width": 622, "mime": "video/mp4", "fps": 25, "url": "1047326445.mp4", "cdn": "akamai_interconnect", "quality": "360p", "id": 1047326445, "origin": "gcs", "height": 360 }, { "profile": 165, "width": 932, "mime": "video/mp4", "fps": 25, "url": "1047326437.mp4", "cdn": "akamai_interconnect", "quality": "540p", "id": 1047326437, "origin": "gcs", "height": 540 } ] } }, "video": { "version": { "current": null, "available": null }, "height": 540, "duration": 401, "thumbs": { "640": "712851375_640.jpg", "960": "712851375_960.jpg", "base": "712851375" }, "id": 279550927, "default_to_hd": 0, "url": null, "privacy": "disable", "unlisted_hash": null }}我從中刪除了很多對象以便更好地閱讀。我想要“url”：“1047326445.mp4”，來自“漸進式數組和來自視頻對象中的“640”變量的字符串。
2 回答
叮當貓咪
TA貢獻1776條經驗 獲得超12個贊
我通過這個得到了渴望的結果，
string json = null;
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(urlJSONcall);
HttpWebResponse response = null;
try
{
response = (HttpWebResponse)request.GetResponse();
var responseStream = response.GetResponseStream();
if ((responseStream != null) && responseStream.CanRead)
{
using (var reader = new System.IO.StreamReader(responseStream))
{
json = reader.ReadToEnd();
}
}
}
finally
{
if (response != null)
{
response.Close();
}
}
var datao = (JObject)JsonConvert.DeserializeObject(json);
//LBresponse.Text = data.ToString();
string urll = (string)datao["request"]["files"]["progressive"][0]["url"];
string thumbnailImage = (string)datao["video"]["thumbs"]["640"];
LBresponse.Text = urll.ToString();
lbltumb.Text = thumbnailImage.ToString();
}
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