我剛剛在我的應用程序中實現了 Google 登錄，但由于某種原因，當用戶單擊 google 登錄按鈕時，它沒有激活 MainActivity。這是當用戶單擊登錄按鈕時激活的方法：private void signIn() { Intent signInIntent = mGoogleSignInClient.getSignInIntent(); startActivityForResult(signInIntent, RC_SIGN_IN);}我必須在我想激活的地方添加活動。通常我將它添加到 Intent 中。但是當我這樣做時：private void signIn() { Intent signInIntent = mGoogleSignInClient.getSignInIntent(); signInIntent.setClass(this, MainActivity.class); startActivityForResult(signInIntent, RC_SIGN_IN);}然后登錄不再起作用。
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溫溫醬
TA貢獻1752條經驗 獲得超4個贊
正如您在此處看到的，在調用登錄意圖后，您必須覆蓋 onActivityResult 方法來處理它：
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
// Result returned from launching the Intent from GoogleSignInClient.getSignInIntent(...);
if (requestCode == RC_SIGN_IN) {
// The Task returned from this call is always completed, no need to attach
// a listener.
Task<GoogleSignInAccount> task = GoogleSignIn.getSignedInAccountFromIntent(data);
handleSignInResult(task);
}
}
然后在您的 handleSignInResult 中，您可以檢查登錄是否成功，然后開始您的活動
private void handleSignInResult(Task<GoogleSignInAccount> completedTask) {
try {
GoogleSignInAccount account = completedTask.getResult(ApiException.class);
// Signed in successfully, start your activity here.
} catch (ApiException e) {
// The ApiException status code indicates the detailed failure reason.
// Please refer to the GoogleSignInStatusCodes class reference for more information.
Log.w(TAG, "signInResult:failed code=" + e.getStatusCode());
updateUI(null);
}
}
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